models.py :
class TrainerProfile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE,
null=True, related_name='trainer_profile')
profile_picture = models.ImageField(blank=True)
phone_regex = RegexValidator(regex=r'^\+?1?\d{9,15}$', message="Phone
number must be entered in the format: '+999999999'. Up to 15 digits
allowed.")
mobile_number = models.CharField(validators=[phone_regex],
max_length=17, blank=True)
location = models.CharField(max_length=200,null=True,blank=True)
gender = models.CharField(choices=GENDER_CHOICES,max_length=150,
blank=True)
cv = models.FileField(blank=True)
approval=models.BooleanField(default=False)
def __str__(self):
return self.user.username
In my template:
<li class="list-group-item">
<b>Download CV</b> <a class="pull-right">{{ trainer.cv }}</a>
</li>
In the TrainerProfileModel ,I have file field called cv . I want to allow users to download the file directly when clicking on the link.Any ways to implement this?
As mentioned in comments use
trainer.cv.url
instead but also there is other approach for this too, take a look at it here.GoodLuck