How to $http Synchronous call with AngularJS

2019-01-01 02:17发布

Sorry for my newbie question, but the AngularJS documentation is not very explicit or extensive for figuring out some basic stuff.

Is there any way to make a synchronous call with AngularJS?

ON A SERVICE:

myService.getByID = function (id) {
    var retval = null;

    $http({
        url: "/CO/api/products/" + id,
        method: "GET"
    }).success(function (data, status, headers, config) {

        retval = data.Data;

    });

    return retval;
}

7条回答
泛滥B
2楼-- · 2019-01-01 02:54

Since sync XHR is being deprecated, it's best not to rely on that. If you need to do a sync POST request, you can use the following helpers inside of a service to simulate a form post.

It works by creating a form with hidden inputs which is posted to the specified URL.

//Helper to create a hidden input
function createInput(name, value) {
  return angular
    .element('<input/>')
    .attr('type', 'hidden')
    .attr('name', name)
    .val(value);
}

//Post data
function post(url, data, params) {

    //Ensure data and params are an object
    data = data || {};
    params = params || {};

    //Serialize params
    const serialized = $httpParamSerializer(params);
    const query = serialized ? `?${serialized}` : '';

    //Create form
    const $form = angular
        .element('<form/>')
        .attr('action', `${url}${query}`)
        .attr('enctype', 'application/x-www-form-urlencoded')
        .attr('method', 'post');

    //Create hidden input data
    for (const key in data) {
        if (data.hasOwnProperty(key)) {
            const value = data[key];
            if (Array.isArray(value)) {
                for (const val of value) {
                    const $input = createInput(`${key}[]`, val);
                    $form.append($input);
                }
            }
            else {
                const $input = createInput(key, value);
                $form.append($input);
            }
        }
    }

    //Append form to body and submit
    angular.element(document).find('body').append($form);
    $form[0].submit();
    $form.remove();
}

Modify as required for your needs.

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