Seeding the random number generator in Javascript

Question

Is it possible to seed the random number generator (Math.random) in Javascript?

Answer 1

To write your own pseudo random generator is quite simple.

The suggestion of Dave Scotese is useful but, as pointed out by others, it is not quite uniformly distributed.

However, it is not because of the integer arguments of sin. It's simply because of the range of sin, which happens to be a one dimensional projection of a circle. If you would take the angle of the circle instead it would be uniform.

So instead of sin(x) use arg(exp(i * x)) / (2 * PI).

If you don't like the linear order, mix it a bit up with xor. The actual factor doesn't matter that much either.

To generate n pseudo random numbers one could use the code:

function psora(k, n) {
  var r = Math.PI * (k ^ n)
  return r - Math.floor(r)
}
n = 42; for(k = 0; k < n; k++) console.log(psora(k, n))

Please also note that you cannot use pseudo random sequences when real entropy is needed.

Answer 2

NOTE: Despite (or rather, because of) succinctness and apparent elegance, this algorithm is by no means a high-quality one in terms of randomness. Look for e.g. those listed in this answer for better results.

(Originally adapted from a clever idea presented in a comment to another answer.)

var seed = 1;
function random() {
    var x = Math.sin(seed++) * 10000;
    return x - Math.floor(x);
}

You can set seed to be any number, just avoid zero (or any multiple of Math.PI).

The elegance of this solution, in my opinion, comes from the lack of any "magic" numbers (besides 10000, which represents about the minimum amount of digits you must throw away to avoid odd patterns - see results with values 10, 100, 1000). Brevity is also nice.

It's a bit slower than Math.random() (by a factor of 2 or 3), but I believe it's about as fast as any other solution written in JavaScript.

Answer 3

For a number between 0 and 100.

Number.parseInt(Math.floor(Math.random() * 100))

Answer 4

I have written a function that returns a seeded random number, it uses Math.sin to have a long random number and uses the seed to pick numbers from that.

Use :

seedRandom("k9]:2@", 15)

it will return your seeded number the first parameter is any string value ; your seed. the second parameter is how many digits will return.

     function seedRandom(inputSeed, lengthOfNumber){

           var output = "";
           var seed = inputSeed.toString();
           var newSeed = 0;
           var characterArray = ['0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','y','x','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','U','R','S','T','U','V','W','X','Y','Z','!','@','#','$','%','^','&','*','(',')',' ','[','{',']','}','|',';',':',"'",',','<','.','>','/','?','`','~','-','_','=','+'];
           var longNum = "";
           var counter = 0;
           var accumulator = 0;

           for(var i = 0; i < seed.length; i++){
                var a = seed.length - (i+1);
                for(var x = 0; x < characterArray.length; x++){
                     var tempX = x.toString();
                     var lastDigit = tempX.charAt(tempX.length-1);
                     var xOutput = parseInt(lastDigit);
                     addToSeed(characterArray[x], xOutput, a, i); 
                }                  
           }

                function addToSeed(character, value, a, i){
                     if(seed.charAt(i) === character){newSeed = newSeed + value * Math.pow(10, a)}
                }
                newSeed = newSeed.toString();

                var copy = newSeed;
           for(var i=0; i<lengthOfNumber*9; i++){
                newSeed = newSeed + copy;
                var x = Math.sin(20982+(i)) * 10000;
                var y = Math.floor((x - Math.floor(x))*10);
                longNum = longNum + y.toString()
           }

           for(var i=0; i<lengthOfNumber; i++){
                output = output + longNum.charAt(accumulator);
                counter++;
                accumulator = accumulator + parseInt(newSeed.charAt(counter));
           }
           return(output)
      }

Answer 5

No, it is not, but it's fairly easy to write your own generator, or better yet use an existing one. Check out: this related question.

Also, see David Bau's blog for more information on seeding.

Answer 6

No, but here's a simple pseudorandom generator, an implementation of Multiply-with-carry I adapted from Wikipedia (has been removed since):

var m_w = 123456789;
var m_z = 987654321;
var mask = 0xffffffff;

// Takes any integer
function seed(i) {
    m_w = (123456789 + i) & mask;
    m_z = (987654321 - i) & mask;
}

// Returns number between 0 (inclusive) and 1.0 (exclusive),
// just like Math.random().
function random()
{
    m_z = (36969 * (m_z & 65535) + (m_z >> 16)) & mask;
    m_w = (18000 * (m_w & 65535) + (m_w >> 16)) & mask;
    var result = ((m_z << 16) + (m_w & 65535)) >>> 0;
    result /= 4294967296;
    return result;
}

EDIT: fixed seed function by making it reset m_z
EDIT2: Serious implementation flaws have been fixed