Two arrays in foreach loop

Question

I want to generate a selectbox using two arrays, one containing the country codes and another containing the country names.

This is an example:

<?php
    $codes = array('tn','us','fr');
    $names = array('Tunisia','United States','France');

    foreach( $codes as $code and $names as $name ) {
        echo '<option value="' . $code . '">' . $name . '</option>';
    }
?>

This method didn't work for me. Any suggestions?

Answer 1

Walk it out...

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');

• PHP 5.3+

  array_walk($codes, function ($code,$key) use ($names) { 
      echo '<option value="' . $code . '">' . $names[$key] . '</option>';
  });
  

• Before PHP 5.3

  array_walk($codes, function ($code,$key,$names){ 
      echo '<option value="' . $code . '">' . $names[$key] . '</option>';
  },$names);
  

• or combine

  array_walk(array_combine($codes,$names), function ($name,$code){ 
      echo '<option value="' . $code . '">' . $name . '</option>';
  })
  

• in select

  array_walk(array_combine($codes,$names), function ($name,$code){ 
      @$opts = '<option value="' . $code . '">' . $name . '</option>';
  })
  echo "<select>$opts</select>";
  

demo

Answer 2

I think the simplest way is just to use the for loop this way:

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');

for($i = 0; $i < sizeof($codes); $i++){
    echo '<option value="' . $codes[$i] . '">' . $names[$i] . '</option>';
}

Answer 3

foreach only works with a single array. To step through multiple arrays, it's better to use the each() function in a while loop:

while(($code = each($codes)) && ($name = each($names))) {
    echo '<option value="' . $code['value'] . '">' . $name['value'] . '</option>';
}

each() returns information about the current key and value of the array and increments the internal pointer by one, or returns false if it has reached the end of the array. This code would not be dependent upon the two arrays having identical keys or having the same sort of elements. The loop terminates when one of the two arrays is finished.

Answer 4

I solved a problem like yours by this way:

foreach(array_keys($idarr) as $i) {
 echo "Student ID: ".$idarr[$i]."<br />";
 echo "Present: ".$presentarr[$i]."<br />";
 echo "Reason: ".$reasonarr[$i]."<br />";
 echo "Mark: ".$markarr[$i]."<br />";
}

Answer 5

This worked for me:

$codes = array('tn', 'us', 'fr');
$names = array('Tunisia', 'United States', 'France');
foreach($codes as $key => $value) {
    echo "Code is: " . $codes[$key] . " - " . "and Name: " . $names[$key] . "<br>";
}

Answer 6

Instead of foreach loop, try this (only when your arrays have same length).

$number = COUNT($_POST["codes "]);//count how many arrays available
if($number > 0)  
{  
  for($i=0; $i<$number; $i++)//loop thru each arrays
  {
    $codes =$_POST['codes'][$i];
    $names =$_POST['names'][$i];
    //ur code in here
  }
}