Regular expression to validate windows and linux p

Question

I am trying to write a function which will validate weather the given path is valid in Linux/Windows with file extension.

ex:

Windows path: D:\DATA\My_Project\01_07_03_061418738709443.doc
Linux path: /source_data/files/08_05_09_1418738709443.pdf

The code that I have tried is

static String REMOTE_LOCATION_WIN_PATTERN = "([a-zA-Z]:)?(\\\\[a-z  A-Z0-9_.-]+)+.(txt|gif|jpg|png|jpeg|pdf|doc|docx|xls|xlsx|DMS)\\\\?";

static String REMOTE_LOCATION_LINUX_PATTERN = "^(/[^/]*)+.(txt|gif|jpg|png|jpeg|pdf|doc|docx|xls|xlsx|DMS)/?$";

public boolean checkPathValidity(String filePath) {

   Pattern linux_pattern = Pattern.compile(REMOTE_LOCATION_LINUX_PATTERN);
   Pattern win_pattern = Pattern.compile(REMOTE_LOCATION_WIN_PATTERN);
   Matcher m1 = linux_pattern.matcher(filePath);
   Matcher m2 = win_pattern.matcher(filePath);

   if (m1.matches() || m2.matches()) {
      return true;
   } else {
      return false;
   }
}

This function gives result true if path is valid in either windows/linux. The above function is not returning right result for some of the paths that contain dates, _ ? , * in their path.

Answer 1

static String REMOTE_LOCATION_WIN_PATTERN = "([a-zA-Z]:)?(\\\\[a-z  A-Z0-9_.-]+)+.(txt|gif|jpg|png|jpeg|pdf|doc|docx|xls|xlsx|DMS)\\\\?";

static String REMOTE_LOCATION_LINUX_PATTERN = "^(/[^/]*)+.(txt|gif|jpg|png|jpeg|pdf|doc|docx|xls|xlsx|DMS)/?$";

static Pattern linux_pattern = Pattern.compile(REMOTE_LOCATION_LINUX_PATTERN);
static Pattern win_pattern = Pattern.compile(REMOTE_LOCATION_WIN_PATTERN);

static final boolean WINDOWS = System.getProperty("os.name").startsWith("Windows");


public boolean checkPathValidity(String filePath) {
   Matcher m = WINDOWS ? win_pattern.matcher(filePath) : linux_pattern.matcher(filePath);

   return m.matches();    
}