Extract all file name from fileset in XSLT 1.0

2019-08-18 16:36发布

build.xml file

<fileset dir="Windows/" casesensitive="yes" id="filename.list">
    <include name="file1.xml"/>
    <include name="file2.xml"/>
    <include name="file3.xml"/>
</fileset>
<pathconvert property="filename.list.csv" refid="filename.list" pathsep="," />                      

<xslt basedir="Windows/" destdir="/meta-inf" extension=".mf" style="test1.xslt" >
    <mapper type="glob" from="*.xml" to="test1.mf"/>
    <param name="build_date" expression="${build.date}"/>
    <param name="dir" expression="${windows.dir}"/>
    <param name="file_list" expression="${new.filename.list.csv}"/>
</xslt>

I want extract all three files from fileset and use like below:

XSLT File:

<xsl:variable name="docs" select="document('file1.xml') | 
document('file2.xml') | document('file3.xml')"/>

Can anyone help me here?

标签: xml xslt ant
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