MySQL Orderby a number, Nulls last

Question

Currently I am doing a very basic OrderBy in my statement.

SELECT * FROM tablename WHERE visible=1 ORDER BY position ASC, id DESC

The problem with this is that NULL entries for 'position' are treated as 0. Therefore all entries with position as NULL appear before those with 1,2,3,4. eg:

NULL, NULL, NULL, 1, 2, 3, 4

Is there a way to achieve the following ordering:

1, 2, 3, 4, NULL, NULL, NULL.

Answer 1

NULL LAST

SELECT * FROM table_name ORDER BY id IS NULL, id ASC

Answer 2

You can swap out instances of NULL with a different value to sort them first (like 0 or -1) or last (a large number or a letter)...

SELECT field1, IF(field2 IS NULL, 9999, field2) as ordered_field2
  FROM tablename
 WHERE visible = 1
 ORDER BY ordered_field2 ASC, id DESC

Answer 3

You can coalesce your NULLs in the ORDER BY statement:

select * from tablename
where <conditions>
order by
    coalesce(position, 0) ASC, 
    id DESC

If you want the NULLs to sort on the bottom, try coalesce(position, 100000). (Make the second number bigger than all of the other position's in the db.)

Answer 4

MySQL has an undocumented syntax to sort nulls last. Place a minus sign (-) before the column name and switch the ASC to DESC:

SELECT * FROM tablename WHERE visible=1 ORDER BY -position DESC, id DESC

It is essentially the inverse of position DESC placing the NULL values last but otherwise the same as position ASC.

A good reference is here http://troels.arvin.dk/db/rdbms#select-order_by