I just observed a strange issue with libc++ when using SFINAE to detect if a templated type is default constructible.
The following is a minimal example I was able to come up with:
#include <iostream>
#include <type_traits>
template <typename T>
struct Dummy;
template <>
struct Dummy<int>{};
template <typename T, typename = void>
struct has_dummy : std::false_type {};
template <typename T>
struct has_dummy<C, std::enable_if_t<std::is_default_constructible<Dummy<T>>::value>> : std::true_type{};
int main() {
std::cout << std::boolalpha << has_dummy<int>{}() << '\n';
std::cout << std::boolalpha << has_dummy<double>{}() << '\n';
}
It compiles and outputs the expected lines true
and false
when compiled with g++ or clang++ when using libstdc++
. However when I try to compile it with libc++ (i.e. clang++ -stdlib=libc++ -std=c++1z test.cpp
) I get the following error:
/usr/bin/../include/c++/v1/type_traits:2857:38: error: implicit instantiation of undefined template 'Dummy' : public integral_constant
/usr/bin/../include/c++/v1/type_traits:3166:14: note: in instantiation of template class 'std::__1::is_constructible>' requested here : public is_constructible<_Tp>
test.cpp:14:43: note: in instantiation of template class 'std::__1::is_default_constructible >' requested here
struct has_dummy<T, std::enable_if_t<std::is_default_constructible<Dummy<T>>::value>> : std::true_type{};
test.cpp:18:35: note: during template argument deduction for class template partial specialization
'has_dummy<type-parameter-0-0, typename enable_if<std::is_default_constructible<Dummy<T> >::value, void>::type>' [with T = double]
std::cout << std::boolalpha << has_dummy<double>{}() << '\n';
test.cpp:5:8: note: template is declared here
struct Dummy;
Is this a bug in libc++'s implementation of std::enable_if
or std::is_default_constructible
or is what I'm doing somehow invoking undefined/implementation specific behaviour?
Best Corristo