There are two script files with the following script
//parent.lua
function scope()
local var = "abc"
require "child"
end
//child.lua
print(var)
This way, child.lua will print a nil value because the scope in parent.lua does not expose its local features to the module. I thought it would, since the require directive is stated within this scope and after the declaration of var. My desire is to practically wholly inject all the lines of the child into the parent. The child script is just exported for better readability. How can I pass the local scope? loadfile() did not work, nor did dofile(). The function environment fenv does not harbor local values. debug.setlocal() does not seem to be able to create new variables (also it would require a receiver in the child). Any method besides recompiling the script?
You can with a bit of effort. If your variables in child
are real upvalues you can "link" them to values in your scope
function. If they are global variables (which seems to be the case here), you can map them to an environment using setfenv
and populate that environment with values from your local variables.
The following will print abc
as you'd expect (you can change loadstring
to loadfile
with the same effect):
function vars(f)
local func = debug.getinfo(f, "f").func
local i = 1
local vars = {}
while true do
local name, value = debug.getlocal(f, i)
if not name then break end
if string.sub(name, 1, 1) ~= '(' then vars[name] = value end
i = i + 1
end
i = 1
while func do -- check for func as it may be nil for tail calls
local name, value = debug.getupvalue(func, i)
if not name then break end
vars[name] = value
i = i + 1
end
return vars
end
function parent()
local var = "abc"
local child = loadstring("print(var)")
local env = vars(2) -- grab all local/upvalues for the current function
-- use these values to populate new environment; map to _G for everything else
setmetatable(env, {__index = _G})
setfenv(child, env)
child()
end
parent()
This is all for Lua 5.1, but it's also possible in Lua 5.2.