两个日期之间的SQL时间差导致HH：MM：SS(SQL time difference betwee

2019-06-21 07:58发布

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我面临着一些困难与计算两个日期之间的时间差。

我想是的，我有两个日期，让说

@StartDate = '10/01/2012 08:40:18.000'
@EndDate='10/04/2012 09:52:48.000'

所以在形式的两个日期之间的差值hh:mm:ss是72:42:30 。

我怎样才能得到这样的结果在T-SQL查询？

Answer 1:

declare @StartDate datetime, @EndDate datetime

select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000'

select convert(varchar(5),DateDiff(s, @startDate, @EndDate)/3600)+':'+convert(varchar(5),DateDiff(s, @startDate, @EndDate)%3600/60)+':'+convert(varchar(5),(DateDiff(s, @startDate, @EndDate)%60)) as [hh:mm:ss]

该查询对您有所帮助。

Answer 2:

最短的代码如下：

Select CAST((@EndDateTime-@StartDateTime) as time(0)) '[hh:mm:ss]'

Answer 3:

虽然也许不是最有效的，这会工作：

declare @StartDate datetime, @EndDate datetime

select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000'

select convert(varchar(5),DateDiff(s, @startDate, @EndDate)/3600)+':'+convert(varchar(5),DateDiff(s, @startDate, @EndDate)%3600/60)+':'+convert(varchar(5),(DateDiff(s, @startDate, @EndDate)%60))

如果你可以运行两个选择那么这将是更好，因为你只能做一次DATEDIFF：

declare @StartDate datetime, @EndDate datetime

select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000'
declare @Sec BIGINT

select @Sec = DateDiff(s, @startDate, @EndDate)

select convert(varchar(5),@sec/3600)+':'+convert(varchar(5),@sec%3600/60)+':'+convert(varchar(5),(@sec%60))

Answer 4:

如果你不反对的隐式类型转换，我会提供这种替代解决方案。它是更具可读性更好的格式？你是法官。

DECLARE  @StartDate datetime = '10/01/2012 08:40:18.000'
        ,@EndDate   datetime = '10/04/2012 09:52:48.000'

SELECT
    STR(ss/3600, 5) + ':' + RIGHT('0' + LTRIM(ss%3600/60), 2) + ':' + RIGHT('0' + LTRIM(ss%60), 2) AS [hh:mm:ss]
FROM (VALUES(DATEDIFF(s, @StartDate, @EndDate))) seconds (ss)

Answer 5:

我喜欢制作成一个功能，使其成为可重复使用和您的查询变得更容易阅读的想法：

--get the difference between two datetimes in the format: 'h:m:s'
CREATE FUNCTION getDateDiff(@startDate DATETIME, @endDate DATETIME)
RETURNS VARCHAR(10)
AS BEGIN
    DECLARE @seconds INT = DATEDIFF(s, @startDate, @endDate)
    DECLARE @difference VARCHAR(10) =
    CONVERT(VARCHAR(4), @seconds / 3600) + ':' +
    CONVERT(VARCHAR(2), @seconds % 3600 / 60) + ':' +
    CONVERT(VARCHAR(2), @seconds % 60)
    RETURN @difference
END

用法：

DECLARE @StartDate DATETIME = '10/01/2012 08:40:18.000'
DECLARE @endDate DATETIME = '10/04/2012 09:52:48.000'

SELECT dbo.getDateDiff(@startDate, @endDate) AS DateDifference

结果：

    DateDifference
1   73:12:30

它也更容易，如果你添加填充所以格式始终读取结果hh:mm:ss 。例如，这里是你会怎么做，在SQL Server 2012中或更高版本：

--get the difference between two datetimes in the format: 'hh:mm:ss'
CREATE FUNCTION getDateDiff(@startDate DATETIME, @endDate DATETIME)
RETURNS VARCHAR(10)
AS BEGIN
    DECLARE @seconds INT = DATEDIFF(s, @startDate, @endDate)
    DECLARE @difference VARCHAR(10) =
    FORMAT(@seconds / 3600, '00') + ':' +
    FORMAT(@seconds % 3600 / 60, '00') + ':' +
    FORMAT(@seconds % 60, '00')
    RETURN @difference
END

请注意，这将不会剪辑小时，如果超过2个位数。所以1小时会显示为01:00:00在100小时将显示为100:00:00

Answer 6:

DECLARE @dt1 datetime='2012/06/13 08:11:12', @dt2 datetime='2012/06/12 02:11:12'

SELECT CAST((@dt2-@dt1) as time(0))

Answer 7:

试试这个：

declare @StartDate datetime, @EndDate datetime

select @StartDate = '2016-05-04 10:23:41.083', @EndDate='2016-05-04 10:25:26.053'

select CAST(DateDiff(MI, @startDate, @EndDate)/60 AS varchar)+':'+Cast(DateDiff(MI, @startDate, @EndDate)%60 AS varchar)+':'+cast(DateDiff(s, @startDate, @EndDate)%60 AS varchar) as [hh:mm:ss]

Answer 8:

看看这些。我没有用更多的括号，以保持它的可读性，所以记住乘法加法或减法之前完成。

下面的两个回报：

hr  mins  sec   timediff
73   12    30   73:12:30

这是写入不使用子查询和最易于阅读和理解：

declare @StartDate datetime,
@EndDate datetime

set @StartDate = '10/01/2012 08:40:18.000'
set @EndDate =   '10/04/2012 09:52:48.000' 

select datediff(hour, @StartDate, @EndDate) hr,
   datediff(minute, @StartDate, @EndDate) 
   - datediff(hour, @StartDate, @EndDate) * 60 mins,
   datediff(second, @StartDate, @EndDate) 
   - (datediff(minute, @StartDate, @EndDate) * 60) sec,
   cast(datediff(hour, @StartDate, @EndDate) as varchar)+':'+ 
   cast(datediff(minute, @StartDate, @EndDate) 
   - datediff(hour, @StartDate, @EndDate) * 60 as varchar)+':'+ 
   cast(datediff(second, @StartDate, @EndDate) 
   - (datediff(minute, @StartDate, @EndDate) * 60) as varchar) timediff

这是，如果你有大量的数据，将有更好的表现的一个版本。它需要一个子查询。

declare @StartDate datetime,
@EndDate datetime

set @StartDate = '10/01/2012 08:40:18.000'
set @EndDate =   '10/04/2012 09:52:48.000' 

select s.seconds / 3600  hrs,
s.seconds / 60 - (seconds / 3600 ) * 60 mins,
s.seconds - (s.seconds / 60) * 60   seconds,
cast(s.seconds / 3600 as varchar) + ':' +
cast((s.seconds / 60 - (seconds / 3600 ) * 60) as varchar) + ':' +
cast((s.seconds - (s.seconds / 60) * 60) as varchar) timediff
from (select datediff(second, @StartDate, @EndDate) as seconds) s

Answer 9:

我今天碰到这个职务之际，我试图收集有关的关键领域连接在一起，位于不同表中的字段之间的时间差。这是这种努力的工作代码。（在SQL 2010测试）裸记住我的原始查询共连在共同的关键字段6页的表，在下面的代码我已删除其他表，以不引起用于读取器的任何混淆。

查询的目的是计算变量CreatedUTC＆BackupUTC，其中差额，天表达，字段被称为“之间的差DaysActive。”

declare @CreatedUTC datetime
declare @BackupUtc datetime


SELECT TOP 500

table02.Column_CreatedUTC AS DeviceCreated,
CAST(DATEDIFF(day, table02.Column_CreatedUTC, table03.Column_EndDateUTC) AS nvarchar(5))+ ' Days' As DaysActive,
table03.Column_EndDateUTC AS LastCompleteBackup

FROM

Operations.table01 AS table01

LEFT OUTER JOIN

    dbo.table02 AS table02
ON
    table02.Column_KeyField = table01.Column_KeyField

LEFT OUTER JOIN 

    dbo.table03 AS table03
ON
    table01.Column_KeyField = table03.Column_KeyField

Where table03.Column_EndDateUTC > dateadd(hour, -24, getutcdate()) --Gathers records with an end date in the last 24 hours
AND table02.[Column_CreatedUTC] = COALESCE(@CreatedUTC, table02.[Column_CreatedUTC])
AND table03.[Column_EndDateUTC] = COALESCE(@BackupUTC, table03.[Column_EndDateUTC])

GROUP BY table03.Column_EndDateUTC, table02.Column_CreatedUTC
ORDER BY table02.Column_CreatedUTC ASC, DaysActive, table03.Column_EndDateUTC DESC

输出将是如下：

[DeviceCreated]..[DaysActive]..[LastCompleteBackup]
---------------------------------------------------------
[2/13/12 16:04]..[463 Days]....[5/21/13 12:14]
[2/12/13 22:37]..[97 Days].....[5/20/13 22:10]

Answer 10:

这是一个脚本撰写，然后拷贝到您的脚本文件编写和改变你的requered领域，并得到了放

DECLARE @Sdate DATETIME, @Edate DATETIME, @Timediff VARCHAR(100)
SELECT @Sdate = '02/12/2014 08:40:18.000',@Edate='02/13/2014 09:52:48.000'
SET @Timediff=DATEDIFF(s, @Sdate, @Edate)
SELECT CONVERT(VARCHAR(5),@Timediff/3600)+':'+convert(varchar(5),@Timediff%3600/60)+':'+convert(varchar(5),@Timediff%60) AS TimeDiff

Answer 11:

DECLARE  @StartDate datetime = '10/01/2012 08:40:18.000'
        ,@EndDate   datetime = '10/10/2012 09:52:48.000'
        ,@DaysDifferent int = 0
        ,@Sec BIGINT

select @Sec = DateDiff(s, @StartDate, @EndDate)

IF (DATEDIFF(day, @StartDate, @EndDate) > 0)
    BEGIN
        select @DaysDifferent = DATEDIFF(day, @StartDate, @EndDate)
        select @Sec = @Sec - ( @DaysDifferent * 86400 )
        SELECT LTRIM(STR(@DaysDifferent,3)) +'d '+ LTRIM(STR(@Sec/3600, 5)) + ':' + RIGHT('0' + LTRIM(@Sec%3600/60), 2) + ':' + RIGHT('0' + LTRIM(@Sec%60), 2) AS [dd hh:mm:ss]
    END
ELSE
    BEGIN
        SELECT LTRIM(STR(@DaysDifferent,3)) +'d '+ LTRIM(STR(@Sec/3600, 5)) + ':' + RIGHT('0' + LTRIM(@Sec%3600/60), 2) + ':' + RIGHT('0' + LTRIM(@Sec%60), 2) AS [dd hh:mm:ss]
    END

----------------------------------------------------------------------------------
dd HH:MM:SS
9d 1:12:30

Answer 12:

声明@StartDate日期时间，日期时间@EndDate

set @StartDate = '10/01/2012 08:40:18.000'
set @EndDate =   '10/04/2012 09:52:48.000'

SELECT CONVERT(CHAR(8), CAST(CONVERT(varchar(23),@EndDate,121) AS DATETIME)
-CAST(CONVERT(varchar(23),@StartDate,121)AS DATETIME),8) AS TimeDiff

Answer 13:

declare @StartDate datetime;
declare @EndDate datetime;
select @StartDate = '10/01/2012 08:40:18.000';
select @EndDate='10/04/2012 09:52:48.000';
select  cast(datediff(hour,@StartDate,@EndDate) as varchar(10)) + left(right(cast(cast(cast((@EndDate-@StartDate) as datetime) as time) as varchar(16)),14),6)

文章来源: SQL time difference between two dates result in hh:mm:ss