How to $state.go()

2019-06-20 13:56发布

问题:

Is my $stateProvider:

$stateProvider
.state('home', {
    url : '/',
    templateUrl : '/admindesktop/templates/main/',
    controller : 'AdminDesktopMainController'
}).state('company', {
    url : '/company',
    templateUrl : '/admindesktop/templates/grid/',
    controller : 'CompanyGridController'
}).state('company.detail', {
    url : '/{id:\d+}', //id is 
    templateUrl : '/admindesktop/templates/company/detail/',
    controller : 'CompanyDetailController'
});

It's work for 'company' state (I use ui-sref), but this code not work (called from 'company' state):

$state.go('.detail', {
    id: $scope.selectedItem.id //selectedItem and id is defined
});

I read official docs and answers from StackOverflow, but I don't found solution. I can't use ui-sref, I use ui-grid, and new state opened after select one row from table for editing.

What i do wrong?

回答1:

What would always work is the full state definition:

// instead of this
// $state.go('.detail', {
// use this
$state.go('company.detail', {
    id: $scope.selectedItem.id //selectedItem and id is defined
});

In doc there are defined these options, but they depend on CURRENT state:

to string
Absolute state name or relative state path. Some examples:

  • $state.go('contact.detail') - will go to the contact.detail state
  • $state.go('^') - will go to a parent state
  • $state.go('^.sibling') - will go to a sibling state
  • $state.go('.child.grandchild') - will go to grandchild state


回答2:

My error is in regular expression, really:

.state('company.detail', {
    url : '/{id:\d*}',
    templateUrl : '/admindesktop/templates/company/detail/',
    controller : 'CompanyDetailController'
 })

{id:\d*} worked (integer id).