电子邮件地址验证在安卓上的EditText [复制](Email Address Validat

这个问题已经在这里有一个答案：

我应该如何验证电子邮件地址？ 31个回答

我们怎样才能进行Email Validation上edittext在android ？我已经通过谷歌和SO走了，但我没有找到一个简单的方法来验证它。

Answer 1:

public static boolean isValidEmail(CharSequence target) {
    return (!TextUtils.isEmpty(target) && Patterns.EMAIL_ADDRESS.matcher(target).matches());
}

编辑::它将工作在Android 2.2+起！编辑：新增失踪;

Answer 2:

要执行电子邮件验证，我们有很多方法，但简单和最简单的方法是两种方法 。

1-使用EditText(....).addTextChangedListener其一直处于接通每个输入触发EditText box即EMAIL_ID是无效或有效

/**
 * Email Validation ex:- tech@end.com
*/


final EditText emailValidate = (EditText)findViewById(R.id.textMessage); 

final TextView textView = (TextView)findViewById(R.id.text); 

String email = emailValidate.getText().toString().trim();

String emailPattern = "[a-zA-Z0-9._-]+@[a-z]+\\.+[a-z]+";

emailValidate .addTextChangedListener(new TextWatcher() { 
    public void afterTextChanged(Editable s) { 

    if (email.matches(emailPattern) && s.length() > 0)
        { 
            Toast.makeText(getApplicationContext(),"valid email address",Toast.LENGTH_SHORT).show();
            // or
            textView.setText("valid email");
        }
        else
        {
             Toast.makeText(getApplicationContext(),"Invalid email address",Toast.LENGTH_SHORT).show();
            //or
            textView.setText("invalid email");
        }
    } 
    public void beforeTextChanged(CharSequence s, int start, int count, int after) {
    // other stuffs 
    } 
    public void onTextChanged(CharSequence s, int start, int before, int count) {
    // other stuffs 
    } 
});

2-最简单的方法，使用if-else条件。以使用的getText（）中的EditText框的字符串，并与提供电子邮件的模式进行比较。如果模式不匹配或macthes，按钮的onClick举杯的消息。它会不会在EditText上盒的字符每个输入触发。下面示出简单的例子。

final EditText emailValidate = (EditText)findViewById(R.id.textMessage); 

final TextView textView = (TextView)findViewById(R.id.text); 

String email = emailValidate.getText().toString().trim();

String emailPattern = "[a-zA-Z0-9._-]+@[a-z]+\\.+[a-z]+";

// onClick of button perform this simplest code.
if (email.matches(emailPattern))
{
Toast.makeText(getApplicationContext(),"valid email address",Toast.LENGTH_SHORT).show();
}
else 
{
Toast.makeText(getApplicationContext(),"Invalid email address", Toast.LENGTH_SHORT).show();
}

Answer 3:

我没有这样说：

加入此方法来检查 电子邮件地址 是否有效与否：

private boolean isValidEmailId(String email){

    return Pattern.compile("^(([\\w-]+\\.)+[\\w-]+|([a-zA-Z]{1}|[\\w-]{2,}))@"
              + "((([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?"
              + "[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\."
              + "([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?"
              + "[0-9]{1,2}|25[0-5]|2[0-4][0-9])){1}|"
              + "([a-zA-Z]+[\\w-]+\\.)+[a-zA-Z]{2,4})$").matcher(email).matches();
     }

现在用的EditText的字符串检查：

if(isValidEmailId(edtEmailId.getText().toString().trim())){
  Toast.makeText(getApplicationContext(), "Valid Email Address.", Toast.LENGTH_SHORT).show();
}else{       
  Toast.makeText(getApplicationContext(), "InValid Email Address.", Toast.LENGTH_SHORT).show();
}

完成

Answer 4:

使用来验证您的邮件格式此方法。通过电子邮件作为字符串，如果格式正确，否则为false返回true。

/**
 * validate your email address format. Ex-akhi@mani.com
 */
public boolean emailValidator(String email) 
{
    Pattern pattern;
    Matcher matcher;
    final String EMAIL_PATTERN = "^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$";
    pattern = Pattern.compile(EMAIL_PATTERN);
    matcher = pattern.matcher(email);
    return matcher.matches();
}

Answer 5:

试试这个：

if (!emailRegistration.matches("[a-zA-Z0-9._-]+@[a-z]+.[a-z]+")) {
   editTextEmail.setError("Invalid Email Address");
}

Answer 6:

使用此方法来验证EMAIL： -

 public static boolean isEditTextContainEmail(EditText argEditText) {

            try {
                Pattern pattern = Pattern.compile("^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$");
                Matcher matcher = pattern.matcher(argEditText.getText());
                return matcher.matches();
            } catch (Exception e) {
                e.printStackTrace();
                return false;
            }
        }

让我知道如果您有任何疑问？

Answer 7:

public static boolean isEmailValid(String email) {
    boolean isValid = false;

    String expression = "^[\\w\\.-]+@([\\w\\-]+\\.)+[A-Z]{2,4}$";
    CharSequence inputStr = email;

    Pattern pattern = Pattern.compile(expression, Pattern.CASE_INSENSITIVE);
    Matcher matcher = pattern.matcher(inputStr);
    if (matcher.matches()) {
        isValid = true;
    }
    return isValid;
}

Answer 8:

这是我创建验证的电子邮件地址，如果传递的字符串参数是一个有效的电子邮件地址的样品的方法，它返回true，则返回否则返回false。

private boolean validateEmailAddress(String emailAddress){
    String  expression="^[\\w\\-]([\\.\\w])+[\\w]+@([\\w\\-]+\\.)+[A-Z]{2,4}$";  
       CharSequence inputStr = emailAddress;  
       Pattern pattern = Pattern.compile(expression,Pattern.CASE_INSENSITIVE);  
       Matcher matcher = pattern.matcher(inputStr);  
       return matcher.matches();
}

Answer 9:

试试这个

public static final Pattern EMAIL_ADDRESS_PATTERN = Pattern.compile(

              "[a-zA-Z0-9\\+\\.\\_\\%\\-\\+]{1,256}" +
              "\\@" +
              "[a-zA-Z0-9][a-zA-Z0-9\\-]{0,64}" +
              "(" +
              "\\." +
              "[a-zA-Z0-9][a-zA-Z0-9\\-]{0,25}" +
              ")+"
          );

在TNE编辑文本

final String emailText = email.getText().toString();
EMAIL_ADDRESS_PATTERN.matcher(emailText).matches()

文章来源: Email Address Validation in Android on EditText [duplicate]