正如一个应用程序利用了iPad和iPhone不同的故事板,我想我的应用程序使用一个不同的故事板为iPhone 5,因为在Info.plist中没有选项可为iPhone 5的默认故事板,我会如何编程调用故事板?
我不想使用自动版式为这个应用程序,除非它绝对是最后的手段。 我明白如何如果用户正在使用iPhone 5或其他设备具有相同的屏幕尺寸,以检测。 我只需要知道如何设置默认故事板没有plist中。
正如一个应用程序利用了iPad和iPhone不同的故事板,我想我的应用程序使用一个不同的故事板为iPhone 5,因为在Info.plist中没有选项可为iPhone 5的默认故事板,我会如何编程调用故事板?
我不想使用自动版式为这个应用程序,除非它绝对是最后的手段。 我明白如何如果用户正在使用iPhone 5或其他设备具有相同的屏幕尺寸,以检测。 我只需要知道如何设置默认故事板没有plist中。
我一直在寻找相同的答案几个星期前,这里是我的解决方案,希望可以帮助..
-(void)initializeStoryBoardBasedOnScreenSize {
if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
{ // The iOS device = iPhone or iPod Touch
CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
if (iOSDeviceScreenSize.height == 480)
{ // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone35
UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone35" bundle:nil];
// Instantiate the initial view controller object from the storyboard
UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController];
// Instantiate a UIWindow object and initialize it with the screen size of the iOS device
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
// Set the initial view controller to be the root view controller of the window object
self.window.rootViewController = initialViewController;
// Set the window object to be the key window and show it
[self.window makeKeyAndVisible];
}
if (iOSDeviceScreenSize.height == 568)
{ // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone4" bundle:nil];
// Instantiate the initial view controller object from the storyboard
UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController];
// Instantiate a UIWindow object and initialize it with the screen size of the iOS device
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
// Set the initial view controller to be the root view controller of the window object
self.window.rootViewController = initialViewController;
// Set the window object to be the key window and show it
[self.window makeKeyAndVisible];
}
} else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)
{ // The iOS device = iPad
UISplitViewController *splitViewController = (UISplitViewController *)self.window.rootViewController;
UINavigationController *navigationController = [splitViewController.viewControllers lastObject];
splitViewController.delegate = (id)navigationController.topViewController;
}
}
下的AppDelegate ddiFinishLaunchingWithOptions调用此方法:方法和还没有正确名字忘了你的故事板
希望可以帮助...
这为我工作 - 轻微细化与包装让故事板的功能
-(UIStoryboard*) getStoryboard {
UIStoryboard *storyBoard = nil;
if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad) {
storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPad" bundle:nil];
}else{
if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone){
// The iOS device = iPhone or iPod Touch
CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
if (iOSDeviceScreenSize.height == 480){
// iPhone 3/4x
storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone_4" bundle:nil];
}else if (iOSDeviceScreenSize.height == 568){
// iPhone 5 etc
storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone_5" bundle:nil];
}
}
}
ASSERT(storyBoard);
return storyBoard;
}
UIStoryboard* mainStoryBoard = [self getStoryboard];
self.initialViewController = [mainStoryBoard instantiateInitialViewController];
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
self.window.rootViewController = self.initialViewController;
[self.window makeKeyAndVisible];