Double.TryParse() ignores NumberFormatInfo.NumberG

问题:

I'd like to know if I'm missing something or not... I'm running under the standard Great British culture.

Double result = 0;
if (Double.TryParse("1,2,3", NumberStyles.Any, CultureInfo.CurrentCulture, out result))
{
   Console.WriteLine(result);
}

Expected output would be nothing... "1,2,3" shouldn't parse as a double. However it does. According to the .NET 2.0 MSDN documentation

AllowThousands Indicates that the numeric string can have group separators; for example, separating the hundreds from the thousands. Valid group separator characters are determined by the NumberGroupSeparator and CurrencyGroupSeparator properties of NumberFormatInfo and the number of digits in each group is determined by the NumberGroupSizes and CurrencyGroupSizes properties of NumberFormatInfo.

Allow thousands is included in NumberStyles.Any. The NumberGroupSizes is 3 for my culture. Is this just a bug in the Double.Parse? seems unlikely but I can't spot what I'm doing wrong....

回答1:

It just means the input string can contain zero or more instances of NumberFormatInfo.NumberGroupSeparator. This separator can be used to separate groups of numbers of any size; not just thousands. NumberFormatInfo.NumberGroupSeparator and NumberFormatInfo.NumberGroupSizes are used when formatting decimals as strings. Using Reflector it seems like NumberGroupSeparator is only used to determine if the character is a separator, and if it is, it is skipped. NumberGroupSizes is not used at all.

If you want to validate the string, you could do so using RegEx or write a method to do so. Here's one I just hacked together:

string number = "102,000,000.80";
var parts = number.Split(',');
for (int i = 0; i < parts.Length; i++)
{
    var len = parts[i].Length;
    if ((len != 3) && (i == parts.Length - 1) && (parts[i].IndexOf('.') != 3))
    {
        Console.WriteLine("error");
    }
    else
    {
        Console.WriteLine(parts[i]);
    }
}

// Respecting Culture
static Boolean CheckThousands(String value)
{
    String[] parts = value.Split(new string[] { CultureInfo.CurrentCulture.NumberFormat.NumberGroupSeparator }, StringSplitOptions.None);
    foreach (String part in parts)
    {
        int length = part.Length;
        if (CultureInfo.CurrentCulture.NumberFormat.NumberGroupSizes.Contains(length) == false)
        {
            return false;
        }
    }

    return true;
}