复杂的标题,但这里是什么,我想实现一个简单的例子:
d <- data.frame(v1 = c(1,2,3,4,5,6,7,8),
v2 = c("A","E","C","B","B","C","A","E"))
m <- data.frame(v3 = c("D","E","A","C","D","B"),
v4 = c("d","e","a","c","d","b"))
在值d$v2
应该由值替换m$v4
从价值观匹配d$v2
在m$v3
将得到的数据帧d
应为:
v1 v4
1 a
2 e
3 c
4 b
5 b
6 c
7 a
8 e
我尝试不同的东西,我来最接近的是: d$v2 <- m$v4[which(m$v3 %in% d$v2)]
我尽量避免任何一次for循环! 必须能够:-)莫名其妙...;)
你可以试试:
merge(d,m, by.x="v2", by.y="v3")
v2 v1 v4
1 A 1 a
2 A 7 a
3 B 4 b
4 B 5 b
5 C 3 c
6 C 6 c
7 E 2 e
8 E 8 e
编辑
这是另一种方法,以保持顺序:
data.frame(v1=d$v1, v4=m[match(d$v2, m$v3), 2])
v1 v4
1 1 a
2 2 e
3 3 c
4 4 b
5 5 b
6 6 c
7 7 a
8 8 e
你可以使用一个标准的左连接。
加载数据:
d <- data.frame(v1 = c(1,2,3,4,5,6,7,8), v2 = c("A","E","C","B","B","C","A","E"), stringsAsFactors=F)
m <- data.frame(v3 = c("D","E","A","C","D","B"), v4 = c("d","e","a","c","d","b"), stringsAsFactors=F)
更改列名,这样我可以通过柱“V2”加盟
colnames(m) <- c("v2", "v4")
左连接和保持data.frame d的顺序
library(dplyr)
left_join(d, m)
输出:
v1 v2 v4
1 1 A a
2 2 E e
3 3 C c
4 4 B b
5 5 B b
6 6 C c
7 7 A a
8 8 E e
这会给你所需的输出:
d$v2 <- m$v4[match(d$v2, m$v3)]
匹配函数返回从米矩阵的列V3在值的位置d$v2
被匹配。 一旦获得了索引(使用match()
中,从接入元件m$v4
使用这些索引,以取代在d矩阵,列v2中的元素。
文章来源: Match values in data frame with values in another data frame and replace former with a corresponding pattern from the other data frame