I want to add a new contact using ContactsContract.Intents.Insert
. But the problem is that I don't know how many phone numbers can be. And as I understand I can pass only three phone numbers using PHONE
, SECONDARY_PHONE
, TERTIARY_PHONE
constants. Is there any way to pass more than three numbers?
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试):
问题:
回答1:
Found a solution. It consists in using ContentValues:
Intent intent = new Intent(Intent.ACTION_INSERT);
intent.setType(ContactsContract.Contacts.CONTENT_TYPE);
ArrayList<ContentValues> data = new ArrayList<ContentValues>();
//Filling data with phone numbers
for (int i = 0; i < numberOfPhones; i++) {
ContentValues row = new ContentValues();
row.put(Data.MIMETYPE, Phone.CONTENT_ITEM_TYPE);
row.put(Phone.NUMBER, PhonesNumberList.get(i));
row.put(Phone.TYPE, Phone.TYPE_WORK);
data.add(row);
}
contactIntent.putExtra(ContactsContract.Intents.Insert.NAME, mName);
contactIntent.putParcelableArrayListExtra(ContactsContract.Intents.Insert.DATA, data);
startActivity(contactIntent);
回答2:
Extend Ov3r1oad answer with email:
ContentValues row = new ContentValues();
row.put(ContactsContract.Data.MIMETYPE, ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE);
row.put(ContactsContract.CommonDataKinds.Email.ADDRESS, emailAddress);
row.put(ContactsContract.CommonDataKinds.Email.TYPE, ContactsContract.CommonDataKinds.Email.TYPE_WORK);
data.add(row);