Possible Duplicate:
How to find the 3rd Friday in a month with C#?
Hi everyone,
I've wrote a little console utility that spits out a line into a text file. I want this line to include the second Friday of the current month. Is there any way to do this?
Thanks everyone!
Slight variation on @druttka: using an extension method.
public static DateTime NthOf(this DateTime CurDate, int Occurrence , DayOfWeek Day)
{
var fday = new DateTime(CurDate.Year, CurDate.Month, 1);
var fOc = fday.DayOfWeek == Day ? fday : fday.AddDays(Day - fday.DayOfWeek);
// CurDate = 2011.10.1 Occurance = 1, Day = Friday >> 2011.09.30 FIX.
if (fOc.Month < CurDate.Month) Occurrence = Occurrence+1;
return fOc.AddDays(7 * (Occurrence - 1));
}
Then called it like this:
for (int i = 1; i < 13; i++)
{
Console.WriteLine(new DateTime(2011, i,1).NthOf(2, DayOfWeek.Friday));
}
Untested, but this should grab it.
DateTime today = DateTime.Today;
DateTime secondFriday =
Enumerable.Range(8, 7)
.Select(item => new DateTime(today.Year, today.Month, item))
.Where(date => date.DayOfWeek == DayOfWeek.Friday)
.Single();
I would go for something like this.
public static DateTime SecondFriday(DateTime currentMonth)
{
var day = new DateTime(currentMonth.Year, currentMonth.Month, 1);
day = FindNext(DayOfWeek.Friday, day);
day = FindNext(DayOfWeek.Friday, day.AddDays(1));
return day;
}
private static DateTime FindNext(DayOfWeek dayOfWeek, DateTime after)
{
DateTime day = after;
while (day.DayOfWeek != dayOfWeek) day = day.AddDays(1);
return day;
}
fully tested:
for (int mo = 1; mo <= 12; mo++)
{
DateTime _date = new DateTime(yr, mo, 1);
DayOfWeek day = _date.DayOfWeek;
int d = 0;
if (day == DayOfWeek.Saturday)
d += 7;
var diff = DayOfWeek.Friday - day;
DateTime secFriday = _date.AddDays(diff + 7 + d);
Console.WriteLine(secFriday.ToString("MM\tddd\tdd"));
}
Final results:
Month Date
=====================
01 Fri 14
02 Fri 11
03 Fri 11
04 Fri 08
05 Fri 13
06 Fri 10
07 Fri 08
08 Fri 12
09 Fri 09
10 Fri 14
11 Fri 11
12 Fri 09