How can I add a comma to separate each group of th

问题:

I have a text input field for a form where users are meant to enter a number. I would like to automatically insert a comma after every third digit.

For example, entering '20' would result in '20'. Entering '100' would result in '100'. But if they were to enter '1000', a comma would be inserted between the 1 and the following 0's (e.g., 1,000). Obviously this behaviour would continue should the number reach 7 digits (e.g., 1,000,000).

Is there an easy way to do this? I'm a bit of a newb at all of this, so please answer like you're talking to a child :)

回答1:

The following javascript:

function format(input)
{
    var nStr = input.value + '';
    nStr = nStr.replace( /\,/g, "");
    var x = nStr.split( '.' );
    var x1 = x[0];
    var x2 = x.length > 1 ? '.' + x[1] : '';
    var rgx = /(\d+)(\d{3})/;
    while ( rgx.test(x1) ) {
        x1 = x1.replace( rgx, '$1' + ',' + '$2' );
    }
    input.value = x1 + x2;
}

and the following HTML:

<input type="text" onkeyup="format(this)">

should solve your problem. The key is to use 'onkeyup'.

Try it here http://jsfiddle.net/YUSph/

回答2:

for the fun of it:

'9876543210'
    .split('') // flip the entire string so that we can break every
    .reverse() //   3rd digit, starting from the end
    .join('')
    .split(/(...)/) // split on every 3rd
    .reverse()      // flip the string again, though now each group of 3 is
    .join(',')      //   backwards
    .replace(/,(?=,)|,$|^,/g, '') // remove extra ,
    .replace(/(,|^)(\d)(\d)?(\d)?/g, '$1$4$3$2') // flip each group of digits
// 9,876,543,210

Anyone want to take a stab at making that better?

回答3:

function addCommas(nStr){
        nStr += '';
        x = nStr.split('.');
        x1 = x[0];
        x2 = x.length > 1 ? '.' + x[1] : '';
        var rgx = /(\d+)(\d{3})/;
        while (rgx.test(x1)) {
            x1 = x1.replace(rgx, '$1' + ',' + '$2');
    }
        return x1 + x2;
}

Pass the value of the input into function and set the input with the result returned. You can bind this to an onchange event.

Here is a working example that relies on jquery to bind the change event and set the value: http://jsfiddle.net/TYyfn/

Comma script is from: http://www.mredkj.com/javascript/nfbasic.html

回答4:

Yes, it's not terribly difficult. I believe this reference may give you what you need.

Note that for this to be dynamic (as they type) you'd need to have this wired to the input field change handler. Otherwise, you can wire this to the input field blur handler (which will have the effect of putting the commas in the field when they leave the field).

回答5:

Give this a try: it may need a little tweeking.

1. take the function from above: function addCommas(nStr){...} and put in a js file.

2. add a script link in the page header to jquery library with: src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"

3. be sure your text box has a unique id. ex: id="comma_input".

4. in the same js file add

    $(document).ready(function(){ 
        $('#comma_input').keyup(function(){
            $(this).attr('value',addCommas($(this).attr('value')));
        });
    });
   

回答6:

function addCommas(nStr){
    var offset = nStr.length % 3;
    if (offset == 0)
        return nStr.substring(0, offset) + nStr.substring(offset).replace(/([0-9]{3})(?=[0-9]+)/g, "$1,");
    else
        return nStr.substring(0, offset) + nStr.substring(offset).replace(/([0-9]{3})/g, ",$1");
}


alert(addCommas("1234567"));

回答7:

Another way to do it, no RegEx, just array manipulation:

function decimalMark(s) {
    for (var a = s.split("").reverse(), b = [], i = 0; i < a.length; i++) { 
        if (i && i%3 === 0)
            b.unshift(",");
        b.unshift(a[i]);
    }

    return b.join("");
}

Be sure to pass a string to the function

decimalMark("1234")

回答8:

Simple string solution in pure JS:

function addCommas(e) {
    var tgt = e.target, val = tgt.value.replace(/,/g, ''),
        amt = Math.ceil(val.length/3), newStr = '', x = 0; 
    while ( x <= amt ) {
        newStr += val.slice(x*3,(x+1)*3);
        newStr += ( x < amt-1 ) ? ',' : '';
        x++
    }
    tgt.value = newStr;
}
document.getElementById('test').addEventListener('change', addCommas, false);

Demo: http://jsfiddle.net/kevinvanlierde/TYyfn/141/

回答9:

You can use standart JavaScript functions. Example here; http://jsfiddle.net/azur/jD5pa/

<!DOCTYPE html>
<html>
    <head>
        <meta http-equiv="content-type" content="text/html; charset=UTF-8">
        <title>pure js solution</title>
        <script type='text/javascript'>
            function digitGroup(dInput) {
                var output = "";
                try {
                    dInput = dInput.replace(/[^0-9]/g, ""); // remove all chars including spaces, except digits.
                    var totalSize = dInput.length;
                    for (var i = totalSize - 1; i > -1; i--) {
                        output = dInput.charAt(i) + output;
                        var cnt = totalSize - i;
                        if (cnt % 3 === 0 && i !== 0) {
                            output = " " + output; // seperator is " "
                        }
                    }
                } catch (err)
                {
                    output = dInput; // it won't happen, but it's sweet to catch exceptions.
                }
                return output;
            }
        </script>
    </head>
    <body>
        <input type="text" value="53" onkeyup="this.value = digitGroup(this.value);">
    </body>
</html>

回答10:

var formatNumber = function(num, type) {
    var numSplit, int, dec, type;

    num = Math.abs(num);
    num = num.toFixed(2);

    numSplit = num.split('.')

    int = numSplit[0];
    if (int.length >= 3) {
        int = int.substr(0, int.length - 3) + ',' + int.substr(int.length - 3, 3);
    }

    dec = numSplit[1];

    return (type === 'exp'? sign = '-' : '+') + ' ' + int + '.' + dec;
};