.Continue starts before task is completed

2019-06-16 03:35发布

问题:

I have the following code in C#, VS2012, WPF 4.5. My expectation would be that, .ContinueWith will be executed after the task has finished completely (that's a continuation's whole purpose, isn't it?).

This should result in a value of 2 in finalResult.

int myTestInt = 0;

Task task = Task.Factory.StartNew(async () =>
{
   myTestInt = 1;
   await Task.Delay(TimeSpan.FromSeconds(6));
   myTestInt = 2;

}).ContinueWith(_ =>
   {
      int finalResult = myTestInt;
   });

In fact, finalResult is assigned a value of 1 instead. So it seems like the continuation is started on the await statement already.

Is this the intended behaviour? Am I missing something here? Can't I rely on ContinueWithto start after a task has completely finished?

Update:

Justin's answer just inspired me to check the following:

int myTestInt = 0;
Task task=Task.Factory.StartNew(async () =>
{
   myTestInt = 1;
   await Task.Delay(TimeSpan.FromSeconds(6));
   myTestInt = 2;
});

task.Wait();
int result2 = myTestInt;

finalResult is still set to 1. Is there no way to reliably wait for a task that contains awaits to complete?

回答1:

When you pass an async delegate to Task.Factory.StartNew, the returned Task only represents the first portion of that delegate (up until the time it awaits something that is not already completed).

However, if you pass an async delegate to the new Task.Run method (which was included for this reason), the returned Task represents the entire delegate. So you can use ContinueWith as you expect. (Although await is usually a better option than ContinueWith).

For more information on StartNew vs Run, see Stephen Toub's post on the topic.



回答2:

The await will immediately return control to the calling function, which in this case is the StartNew of your task. This means the task will then complete and execute the ContinueWith. If you really want task to complete before the ContinueWith, then don't await the Task.Delay.



回答3:

I saw this in the MSDN: :-)

public async  void button1_Click(object sender, EventArgs e)
{
    pictureBox1.Image = await Task.Run(async() =>
    {
        using(Bitmap bmp1 = await DownloadFirstImageAsync())
        using(Bitmap bmp2 = await DownloadSecondImageAsync())
        return Mashup(bmp1, bmp2);
    });
}

So do not forget the "async()" !!!