I want to generate random array of size N which only contains 0 and 1 but I want my array have some ratio between 0 and 1. For example 90% of array be 1 and the remaining 10% be 0(but I want this 90% be random along whole array).
right now I have:
randomLabel = np.random.randint(2, size=numbers)
But I can't control the ratio between 0 and 1.
If you want an exact 1:9 ratio:
nums = numpy.ones(1000)
nums[:100] = 0
numpy.random.shuffle(nums)
If you want independent 10% probabilities:
nums = numpy.random.choice([0, 1], size=1000, p=[.1, .9])
or
nums = (numpy.random.rand(1000) > 0.1).astype(int)
Its difficult to get an exact count but you can get approximate answer by assuming that random.random
returns a uniform distribution. This is strictly not the case, but is only approximately true. If you have a truly uniform distribution then it is possible. You can try something like the following:
In [33]: p = random.random(10000)
In [34]: p[p <= 0.1] = 0
In [35]: p[p > 0] = 1
In [36]: sum(p == 0)
Out[36]: 997
In [37]: sum(p == 1)
Out[37]: 9003
Hope this helps ...
Without using numpy, you could do as follows:
import random
percent = 90
nums = percent * [1] + (100 - percent) * [0]
random.shuffle(nums)