Angular 2: getting RouteParams from parent compone

问题:

How do I get the RouteParams from a parent component?

App.ts:

@Component({
  ...
})

@RouteConfig([
  {path: '/', component: HomeComponent, as: 'Home'},
  {path: '/:username/...', component: ParentComponent, as: 'Parent'}
])

export class HomeComponent {
  ...
}

And then, in the ParentComponent, I can easily get my username param and set the child routes.

Parent.ts:

@Component({
  ...
})

@RouteConfig([
  { path: '/child-1', component: ChildOneComponent, as: 'ChildOne' },
  { path: '/child-2', component: ChildTwoComponent, as: 'ChildTwo' }
])

export class ParentComponent {

  public username: string;

  constructor(
    public params: RouteParams
  ) {
    this.username = params.get('username');
  }

  ...
}

But then, how can I get this same 'username' parameter in those child components? Doing the same trick as above, doesn't do it. Because those params are defined at the ProfileComponent or something??

@Component({
  ...
})

export class ChildOneComponent {

  public username: string;

  constructor(
    public params: RouteParams
  ) {
    this.username = params.get('username');
    // returns null
  }

  ...
}

回答1:

UPDATE:

Now that Angular2 final was officially released, the correct way to do this is the following:

export class ChildComponent {

    private sub: any;

    private parentRouteId: number;

    constructor(private route: ActivatedRoute) { }

    ngOnInit() {
        this.sub = this.route.parent.params.subscribe(params => {
            this.parentRouteId = +params["id"];
        });
    }

    ngOnDestroy() {
        this.sub.unsubscribe();
    }
}

---

ORIGINAL:

Here is how i did it using the "@angular/router": "3.0.0-alpha.6" package:

export class ChildComponent {

    private sub: any;

    private parentRouteId: number;

    constructor(
        private router: Router,
        private route: ActivatedRoute) {
    }

    ngOnInit() {
        this.sub = this.router.routerState.parent(this.route).params.subscribe(params => {
            this.parentRouteId = +params["id"];
        });
    }

    ngOnDestroy() {
        this.sub.unsubscribe();
    }
}

In this example the route has the following format: /parent/:id/child/:childid

export const routes: RouterConfig = [
    {
        path: '/parent/:id',
        component: ParentComponent,
        children: [
            { path: '/child/:childid', component: ChildComponent }]
    }
];

回答2:

You shouldn't try to use RouteParams in your ChildOneComponent.

Use RouteRegistry, instead!

@Component({
  ...
})

export class ChildOneComponent {

  public username: string;

  constructor(registry: RouteRegistry, location: Location) {
    route_registry.recognize(location.path(), []).then((instruction) => {
      console.log(instruction.component.params['username']);
    })
  }


  ...
}

UPDATE: As from this pull request (angular beta.9): https://github.com/angular/angular/pull/7163

You can now access to the current instruction without recognize(location.path(), []).

Example:

@Component({
  ...
})

export class ChildOneComponent {

  public username: string;

  constructor(_router: Router) {
    let instruction = _router.currentInstruction();
    this.username = instruction.component.params['username'];
  }

  ...
}

I haven't tried it, yet

Further details here:

https://github.com/angular/angular/blob/master/CHANGELOG.md#200-beta9-2016-03-09 https://angular.io/docs/ts/latest/api/router/Router-class.html

UPDATE 2: A small change as from angular 2.0.0.beta15:

Now currentInstruction is not a function anymore. Moreover, you have to load the root router. (thanks to @Lxrd-AJ for reporting)

@Component({
  ...
})

export class ChildOneComponent {

  public username: string;

  constructor(_router: Router) {
    let instruction = _router.root.currentInstruction;
    this.username = instruction.component.params['username'];
  }

  ...
}

回答3:

As mentioned by Günter Zöchbauer, I used the comment at https://github.com/angular/angular/issues/6204#issuecomment-173273143 to address my problem. I used the Injector class from angular2/core to fetch the routeparams of the parent. Turns out angular 2 does not handle deeply nested routes. Maybe they'll add that in the future.

constructor(private _issueService: IssueService,
            private _injector: Injector) {}

getIssues() {
    let id = this._injector.parent.parent.get(RouteParams).get('id');
    this._issueService.getIssues(id).then(issues => this.issues = issues);
}

回答4:

I found an ugly but working solution, by requesting the parent (precisely the 2nd ancestor) injector, and by getting the RouteParams from here.

Something like

@Component({
  ...
})
export class ChildOneComponent {
  public username: string;

  constructor(injector: Injector) {
    let params = injector.parent.parent.get(RouteParams);

    this.username = params.get('username');
  }
}

回答5:

RC5 + @angular/router": "3.0.0-rc.1 SOLUTION: It seems that this.router.routerState.queryParams has been deprecated. You can get the parent route params this way:

constructor(private activatedRoute: ActivatedRoute) {
}    

this.activatedRoute.parent.params.subscribe(
  (param: any) => {
    let userId = param['userId'];
    console.log(userId);
  });

回答6:

You can take component of parent route inside of child component from injector and then get any from child component. In you case like this

@Component({
  ...
})

export class ChildOneComponent {

  public username: string;

  constructor(
    public params: RouteParams
    private _injector: Injector

  ) {
    var parentComponent = this._injector.get(ParentComponent)

    this.username = parentComponent.username;
    //or
    this.username = parentComponent.params.get('username');
  }

  ...
}

回答7:

Passing Injector instance to constructor in child component may not be good if you want to write unit tests for your code.

The easiest way to work around this is to have a service class in the parent component, in which you save your required params.

@Component({
    template: `<div><router-outlet></router-outlet></div>`,
    directives: [RouterOutlet],
    providers: [SomeServiceClass]
})
@RouteConfig([
    {path: "/", name: "IssueList", component: IssueListComponent, useAsDefault: true}
])
class IssueMountComponent {
    constructor(routeParams: RouteParams, someService: SomeServiceClass) {
        someService.id = routeParams.get('id');
    }
}

Then you just inject the same service to child components and access the params.

@Component({
    template: `some template here`
})
class IssueListComponent implements OnInit {
    issues: Issue[];
    constructor(private someService: SomeServiceClass) {}

    getIssues() {
        let id = this.someService.id;
        // do your magic here
    }

    ngOnInit() {
        this.getIssues();
    }
}

Note that you should scope such service to your parent component and its child components using "providers" in parent component decorator.

I recommend this article about DI and scopes in Angular 2: http://blog.thoughtram.io/angular/2015/08/20/host-and-visibility-in-angular-2-dependency-injection.html

回答8:

In RC6, router 3.0.0-rc.2 (probably works in RC5 as well), you can take route params from the URL as a snapshot in case that params won't change, without observables with this one liner:

this.route.snapshot.parent.params['username'];

Don't forget to inject ActivatedRoute as follows:

constructor(private route: ActivatedRoute) {};

回答9:

With RxJS's Observable.combineLatest, we can get something close to the idiomatic params handling:

import 'rxjs/add/operator/combineLatest';

import {Component} from '@angular/core';
import {ActivatedRoute, Params} from '@angular/router';
import {Observable} from 'rxjs/Observable';

@Component({ /* ... */ })
export class SomeChildComponent {
  email: string;
  id: string;

  constructor(private route: ActivatedRoute) {}

  ngOnInit() {
    Observable.combineLatest(this.route.params, this.route.parent.params)
        .forEach((params: Params[]) => {
          this.id = params[0]['id'];
          this.email = params[1]['email'];
        });
  }
}

回答10:

I ended up writing this kind of hack for Angular 2 rc.1

import { Router } from '@angular/router-deprecated';
import * as _ from 'lodash';

interface ParameterObject {
  [key: string]: any[];
};

/**
 * Traverse route.parent links until root router and check each level
 * currentInstruction and group parameters to single object.
 *
 * e.g.
 * {
 *   id: [314, 593],
 *   otherParam: [9]
 * }
 */
export default function mergeRouteParams(router: Router): ParameterObject {
  let mergedParameters: ParameterObject = {};
  while (router) {
    let currentInstruction = router.currentInstruction;
    if (currentInstruction) {
      let currentParams = currentInstruction.component.params;
      _.each(currentParams, (value, key) => {
        let valuesForKey = mergedParameters[key] || [];
        valuesForKey.unshift(value);
        mergedParameters[key] = valuesForKey;
      });
    }
    router = router.parent;
  }
  return mergedParameters;
}

Now in view I collect parameters in view instead of reading RouteParams I just get them through router:

@Component({
  ...
})

export class ChildishComponent {

  constructor(router: Router) {
    let allParams = mergeRouteParams(router);
    let parentRouteId = allParams['id'][0];
    let childRouteId = allParams['id'][1];
    let otherRandomParam = allParams.otherRandomParam[0];
  }

  ...
}  

回答11:

In FINAL with little help of RXJS you can combine both maps (from child and parent):

(route) => Observable
    .zip(route.params, route.parent.params)
    .map(data => Object.assign({}, data[0], data[1]))

Other questions one might have:

• Is it really a good idea to use above - because of coupling (couple child component with parent's param's - not on api level - hidden coupling),
• Is it proper approach in term of RXJS (it would require hardcore RXJS user feedback ;)

回答12:

You can do it on the snapshot with the following, but if it changes, your id property will not be updated.

This example also shows how you can subscribe to all ancestor parameter changes and look for the one you are interested in by merging all of the parameter observables. However, be careful with this method because there could be multiple ancestors that have the same parameter key/name.

import { Component } from '@angular/core';
import { ActivatedRoute, Params, ActivatedRouteSnapshot } from '@angular/router';
import { Observable } from 'rxjs/Observable';
import { Subscription } from 'rxjs/Subscription';
import 'rxjs/add/observable/merge';

// This traverses the route, following ancestors, looking for the parameter.
function getParam(route: ActivatedRouteSnapshot, key: string): any {
  if (route != null) {
    let param = route.params[key];
    if (param === undefined) {
      return getParam(route.parent, key);
    } else {
      return param;
    }
  } else {
    return undefined;
  }
}

@Component({ /* ... */ })
export class SomeChildComponent {

  id: string;

  private _parameterSubscription: Subscription;

  constructor(private route: ActivatedRoute) {
  }

  ngOnInit() {
    // There is no need to do this if you subscribe to parameter changes like below.
    this.id = getParam(this.route.snapshot, 'id');

    let paramObservables: Observable<Params>[] =
      this.route.pathFromRoot.map(route => route.params);

    this._parametersSubscription =
      Observable.merge(...paramObservables).subscribe((params: Params) => {
        if ('id' in params) {
          // If there are ancestor routes that have used
          // the same parameter name, they will conflict!
          this.id = params['id'];
        }
      });
  }

  ngOnDestroy() {
    this._parameterSubscription.unsubscribe();
  }
}