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问题:

Each pom.xml have:

<groupId>com.vendor</groupId>
<artifactId>product</artifactId>
<version>1.0.13.0-dev</version>  <!-- THIS FIELD -->
<packaging>war</packaging>

version piece is useful to bunch with application so user can see and report them.

But I dislike code duplication and look for a way to avoid putting property file with version info to VCS (Git/SVN) because each time I bump version I must commit into two places (pom.xml and version.properties).

Which way can I make version properties from pom.xml programmatically available in Java application?

回答1:

Have a look at the Maven Resources Plugin. In your version.properties (should be in the resources folder), define a line like version=${project.version}. Make sure to turn on filtering for the plugin (all described in detail at the link above) and you should be good to go!

Just run mvn resources:resources (or mvn compile) and check the generated file.

回答2:

Found a solution to use the maven-war-plugin to be more elegant.

<plugin>
    <groupId>org.apache.maven.plugins</groupId>
    <artifactId>maven-war-plugin</artifactId>
    <version>2.3</version>
    <configuration>
       <webResources>
           <resource>
               <targetPath>WEB-INF/views/jsp</targetPath>
               <directory>${basedir}/src/main/webapp/WEB-INF/views/jsp</directory>
               <includes>
                  <include>footer.jsp</include>
               </includes>
               <filtering>true</filtering>
          </resource>
      </webResources>
  </configuration>
</plugin>

footer.jsp then had:

Application Version: ${project.version}

回答3:

My personal production solution below.

pom.xml:

<?xml version="1.0" encoding="utf-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">

    <version>1.0.13.0-dev</version>

    <build>
        <resources>
            <resource>
                <directory>src/main/resources</directory>
                <filtering>true</filtering>
            </resource>
        </resources>
     ...

base.jsp:

<%@taglib prefix="spring" uri="http://www.springframework.org/tags"%>
<!DOCTYPE html>
<html>
<head></head>
<body>
   <a href='<c:url value="/"/>'>
     <spring:eval expression="@props.getProperty('version')"/>
   </a>
   <jsp:include page="${contentPage}" />
</body>
</html>

proj.properties:

version=${project.version}

applicationContext.xml:

<bean id="props" class="org.springframework.beans.factory.config.PropertiesFactoryBean" autowire="byName" >
    <property name="location" value="classpath:proj.properties"/>
</bean>

<bean id="propertyConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
    <property name="location" value="classpath:proj.properties"/>
</bean>

or just

<util:properties id="props" location="classpath:proj.properties"/>

回答4:

You can simply configure the maven-war-plugin, maven-jar-plugin, maven-ear-plugin like the following:

 <plugin>
   <groupId>org.apache.maven.plugins</groupId>
   <artifactId>maven-war-plugin</artifactId>
   <version>${maven-war-plugin.version}</version>
   <configuration>
     <archive>
       <addMavenDescriptor>true</addMavenDescriptor>
       <index>true</index>
       <manifest>
         <addDefaultImplementationEntries>true</addDefaultImplementationEntries>
         <addDefaultSpecificationEntries>true</addDefaultSpecificationEntries>
       </manifest>
       <manifestEntries>
          <artifactId>${project.artifactId}</artifactId>
          <groupId>${project.groupId}</groupId>
          <version>${project.version}</version>
       </manifestEntries>
     </archive>
   </configuration>
 </plugin>

Reading information from manifest.mf can be done using jacabi.