Required_if laravel with multiple value

2019-06-14 23:31发布

问题:

i have dropdown menu like this

<select name="selection">
   <option value="1">Option 1</option>
   <option value="2">Option 2</option>
   <option value="3">Option 3</option>
</select>
<input type="text" name="stext">

i want in laravel

public static myfunction(){
   $input = \Input::only('selection','stext');
   $rule = array(
      'selection' => 'required',
      'stext' => 'required_if:selection,2,3',
   );
   $validate = \Validator::make($input,$rule);
}

but if i select option 1, stext still required. why? how i can fix it?

thanks before.

回答1:

I think that the require_if validation accept only one value per time. Try to change your validation code as below:

$rule = array(
  'selection' => 'required',
  'stext' => 'required_if:selection,2|required_if:selection,3',
);

EDIT: Check LePhleg answer, is more cleaner. At the time of the answer that was not possible, just check the question, he was using the same method but not worked.



回答2:

You just have to pass all the values as parameters separated by comma:

$rules = array(
      'selection' => 'required',
      'stext'     => 'required_if:selection,2,3'
);


回答3:

try this one

if single match value then used like that

'stext'     => 'required_if:selection,2'

if you have multiple value then used like that (separated by comma)

'stext'     => 'required_if:selection,2,3'

for more information see documentation required_if



回答4:

You can go ahead with sometimes validation for laravel. you can define a custom closure as in the below example

public static myfunction(){
   $input = \Input::only('selection','stext');
   $rule = array(
      'selection' => 'required'
   );
$validator->sometimes('stext', 'required', function($input){
    return (($input->selection == 1) || ($input->selection == 2));
});
   $validate = \Validator::make($input,$rule);
}