MATLAB parfor is slower than for — what is wrong?

问题:

the code I\'m dealing with has loops like the following:

bistar = zeros(numdims,numcases); 
parfor hh=1:nt       
  bistar = bistar +  A(:,:,hh)*data(:,:,hh+1)\' ;
end   

for small nt (10).

After timing it, it is actually 100 times slower than using the regular loop!!! I know that parfor can do parallel sums, so I\'m not sure why this isn\'t working.

I run

matlabpool

with the out-of-the-box configurations before running my code.

I\'m relatively new to matlab, and just started to use the parallel features, so please don\'t assume that I\'m am not doing something stupid.

Thanks!

PS: I\'m running the code on a quad core so I would expect to see some improvements.

回答1:

Making the partitioning and grouping the results (overhead in dividing the work and gathering results from the several threads/cores) is high for small values of nt. This is normal, you would not partition data for easy tasks that can be performed quickly in a simple loop.

Always perform something challenging inside the loop that is worth the partitioning overhead. Here is a nice introduction to parallel programming.

The threads come from a thread pool so the overhead of creating the threads should not be there. But in order to create the partial results n matrices from the bistar size must be created, all the partial results computed and then all these partial results have to be added (recombining). In a straight loop, this is with a high probability done in-place, no allocations take place.

The complete statement in the help (thanks for your link hereunder) is:

If the time to compute f, g, and h is large, parfor will be significantly faster than the corresponding for statement, even if n is relatively small.

So you see they mean exactly the same as what I mean, the overhead for small n values is only worth the effort if what you do in the loop is complex/time consuming enough.

回答2:

Parforcomes with a bit of overhead. Thus, if nt is really small, and if the computation in the loop is done very quickly (like an addition), the parfor solution is slower. Furthermore, if you run parforon a quad-core, speed gain will be close to linear for 1-3 cores, but less if you use 4 cores, since the last core also needs to run system processes.

For example, if parfor comes with 100ms of overhead, and the computation in the loop takes 5ms, and if we assume that speed gain is linear up to 4 cores with a coefficient of 1 (i.e. using 4 cores makes the computation 4 times faster), nt needs to be about 30 for you to achieve a speed gain with parfor (150ms with for, 132ms with parfor). If you were to run only 10 iterations, parfor would be slower (50ms with for, 112ms with parfor).

You can calculate the overhead on your machine by comparing execution time with 1 worker vs 0 workers, and you can estimate speed gain by making a liner fit through the execution times with 1 to 4 workers. Then you\'ll know when it\'s useful to use parfor.

回答3:

Besides the bad performance because of the communication overhead (see other answers), there is another reason not to use parfor in this case. Everything which is done within the parfor in this case uses built-in multithreading. Assuming all workers are running on the same PC there is no advantage because a single call already uses all cores of your processor.