For a given table 'foo', I need a query to generate a set of tables that have foreign keys that point to foo. I'm using Oracle 10G.
问题:
回答1:
This should work (or something close):
select table_name
from all_constraints
where constraint_type='R'
and r_constraint_name in
(select constraint_name
from all_constraints
where constraint_type in ('P','U')
and table_name='<your table here>');
回答2:
The following statement should give the children and all of their descendents. I have tested it on an Oracle 10 database.
SELECT level, main.table_name parent,
link.table_name child
FROM user_constraints main, user_constraints link
WHERE main.constraint_type IN ('P', 'U')
AND link.r_constraint_name = main.constraint_name
START WITH main.table_name LIKE UPPER('&&table_name')
CONNECT BY main.table_name = PRIOR link.table_name
ORDER BY level, main.table_name, link.table_name
回答3:
Here's how to take Mike's query one step further to get the column names from the constraint names:
select * from user_cons_columns
where constraint_name in (
select constraint_name
from all_constraints
where constraint_type='R'
and r_constraint_name in
(select constraint_name
from all_constraints
where constraint_type in ('P','U')
and table_name='<your table name here>'));
回答4:
link to Oracle Database Online Documentation
You may want to explore the Data Dictionary views. They have the prefixes:
- User
- All
- DBA
sample:
select * from dictionary where table_name like 'ALL%'
Continuing Mike's example, you may want to generate scripts to enable/disable the constraints. I only modified the 'select' in the first row.
select 'alter table ' || TABLE_NAME || ' disable constraint ' || CONSTRAINT_NAME || ';'
from all_constraints
where constraint_type='R'
and r_constraint_name in
(select constraint_name
from all_constraints
where constraint_type in ('P','U')
and table_name='<your table here>');
回答5:
I know it's kinda late to answer but let me answer anyway, some of the answers above are quite complicated hence here is a much simpler take.
`SELECT a.table_name child_table, a.column_name child_column, a.constraint_name, b.table_name parent_table, b.column_name parent_column FROM all_cons_columns a JOIN all_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name join all_cons_columns b on c.owner = b.owner and c.r_constraint_name = b.constraint_name WHERE c.constraint_type = 'R' AND a.table_name = 'your table name'`
回答6:
select distinct table_name, constraint_name, column_name, r_table_name, position, constraint_type
from (
SELECT uc.table_name,
uc.constraint_name,
cols.column_name,
(select table_name from user_constraints where constraint_name = uc.r_constraint_name)
r_table_name,
(select column_name from user_cons_columns where constraint_name = uc.r_constraint_name and position = cols.position)
r_column_name,
cols.position,
uc.constraint_type
FROM user_constraints uc
inner join user_cons_columns cols on uc.constraint_name = cols.constraint_name
where constraint_type != 'C'
)
start with table_name = '&&tableName' and column_name = '&&columnName'
connect by nocycle
prior table_name = r_table_name
and prior column_name = r_column_name;
回答7:
Download the Oracle Reference Guide for 10G which explains the data dictionary tables.
The answers above are good but check out the other tables which may relate to constraints.
SELECT * FROM DICT WHERE TABLE_NAME LIKE '%CONS%';
Finally, get a tool like Toad or SQL Developer which allows you to browse this stuff in a UI, you need to learn to use the tables but you should use a UI also.