I have the below text file that I would need some help with parsing out IP addresses.
The text file is of the form
abc 10.1.1.1/32 aabbcc
def 11.2.0.0/16 eeffgg
efg 0.0.0.0/0 ddeeff
In other words, a bunch of IP networks exist as part of a log file. The output should be provided as below:
10.1.1.1/32
11.2.0.0/16
0.0.0.0/0
I have the below code but does not output the required information
file = open(filename, 'r')
for eachline in file.readlines():
ip_regex = re.findall(r'(?:\d{1,3}\.){3}\d{1,3}', eachline)
print ip_regex
First, your regex doesn't even attempt to capture anything but four dotted numbers, so of course it's not going to match anything else, like a /32
on the end. if you just add, e.g., /\d{1,2}
to the end, it'll fix that:
(?:\d{1,3}\.){3}\d{1,3}/\d{1,2}
Debuggex Demo
However, if you don't understand regular expressions well enough to understand that, you probably shouldn't be using a regex as a piece of "magic" that you'll never be able to debug or extend. It's a bit more verbose with str
methods like split
or find
, but maybe easier to understand for a novice:
for line in file:
for part in line.split()
try:
address, network = part.split('/')
a, b, c, d = address.split('.')
except ValueError:
pass # not in the right format
else:
# do something with part, or address and network, or whatever
As a side note, depending on what you're actually doing with these things, you might want to use the ipaddress
module (or the backport on PyPI for 2.6-3.2) rather than string parsing:
>>> import ipaddress
>>> s = '10.1.1.1/32'
>>> a = ipaddress.ip_network('10.1.1.1/32')
You can combine that with either of the above:
for line in file:
for part in line.split():
try:
a = ipaddress.ip_network(part)
except ValueError:
pass # not the right format
else:
# do something with a and its nifty methods
In this particular case, a regex might be overkill, you could use split
with open(filename) as f:
ipList = [line.split()[1] for line in f]
This should produce a list of strings, which are the ip addresses.