How to put a byte array into XML in Scala

I'm interacting with a .Net web service. According to the service description the server is expecting a base64Binary type.

This is how I'm trying to build the SOAP packet:

  <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
    <soap:Header>
    </soap:Header>
    <soap:Body>
      <uploadFile xmlns="http://localhost/">
        <FileDetails>
          <ReferenceNumber>123</ReferenceNumber>
          <FileName>testfile</FileName>
          <FullFilePath>file</FullFilePath>
          <FileType>1</FileType>
          <FileContents>{request.getContent().array()}</FileContents>
         </FileDetails>
        </uploadFile>
      </soap:Body>
   </soap:Envelope>

In the snippet above the request.getContent().array() is an HTTP request I'm receiving from a mobile application developed in PhoneGap.

The server responds that the FileContents is invalid. Any ideas?

Your current version is just writing the bytes (I'm assuming request.getContent().array() is an array of bytes) as space-separated base-10 integers:

scala> val bytes = 1 to 10 map(_.toByte) toArray
bytes: Array[Byte] = Array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)

scala> <FileContents>{bytes}</FileContents>
res0: scala.xml.Elem = <FileContents>1 2 3 4 5 6 7 8 9 10</FileContents>

This definitely isn't what you want. You can use a library like Apache Commons Codec to encode the byte array as a string (here I'm using the Base64 encoder):

scala> import org.apache.commons.codec.binary.Base64
import org.apache.commons.codec.binary.Base64

scala> <FileContents>{Base64.encodeBase64String(bytes)}</FileContents>
res1: scala.xml.Elem = <FileContents>AQIDBAUGBwgJCg==</FileContents>

You might have to tinker with the options a bit, but this is much more likely to be what you need.