Python sum, why not strings? [closed]

问题:

Python has a built in function sum, which is effectively equivalent to:

def sum2(iterable, start=0):
    return start + reduce(operator.add, iterable)

for all types of parameters except strings. It works for numbers and lists, for example:

 sum([1,2,3], 0) = sum2([1,2,3],0) = 6    #Note: 0 is the default value for start, but I include it for clarity
 sum({888:1}, 0) = sum2({888:1},0) = 888

Why were strings specially left out?

 sum( ['foo','bar'], '') # TypeError: sum() can't sum strings [use ''.join(seq) instead]
 sum2(['foo','bar'], '') = 'foobar'

I seem to remember discussions in the Python list for the reason, so an explanation or a link to a thread explaining it would be fine.

Edit: I am aware that the standard way is to do "".join. My question is why the option of using sum for strings was banned, and no banning was there for, say, lists.

Edit 2: Although I believe this is not needed given all the good answers I got, the question is: Why does sum work on an iterable containing numbers or an iterable containing lists but not an iterable containing strings?

回答1:

Python tries to discourage you from "summing" strings. You're supposed to join them:

"".join(list_of_strings)

It's a lot faster, and uses much less memory.

A quick benchmark:

$ python -m timeit -s 'import operator; strings = ["a"]*10000' 'r = reduce(operator.add, strings)'
100 loops, best of 3: 8.46 msec per loop
$ python -m timeit -s 'import operator; strings = ["a"]*10000' 'r = "".join(strings)'
1000 loops, best of 3: 296 usec per loop

Edit (to answer OP's edit): As to why strings were apparently "singled out", I believe it's simply a matter of optimizing for a common case, as well as of enforcing best practice: you can join strings much faster with ''.join, so explicitly forbidding strings on sum will point this out to newbies.

BTW, this restriction has been in place "forever", i.e., since the sum was added as a built-in function (rev. 32347)

回答2:

You can in fact use sum(..) to concatenate strings, if you use the appropriate starting object! Of course, if you go this far you have already understood enough to use "".join(..) anyway..

>>> class ZeroObject(object):
...  def __add__(self, other):
...   return other
...
>>> sum(["hi", "there"], ZeroObject())
'hithere'

回答3:

Here's the source: http://svn.python.org/view/python/trunk/Python/bltinmodule.c?revision=81029&view=markup

In the builtin_sum function we have this bit of code:

     /* reject string values for 'start' parameter */
        if (PyObject_TypeCheck(result, &PyBaseString_Type)) {
            PyErr_SetString(PyExc_TypeError,
                "sum() can't sum strings [use ''.join(seq) instead]");
            Py_DECREF(iter);
            return NULL;
        }
        Py_INCREF(result);
    }

So.. that's your answer.

It's explicitly checked in the code and rejected.

回答4:

From the docs:

The preferred, fast way to concatenate a sequence of strings is by calling ''.join(sequence).

By making sum refuse to operate on strings, Python has encouraged you to use the correct method.

回答5:

Short answer: Efficiency.

Long answer: The sum function has to create an object for each partial sum.

Assume that the amount of time required to create an object is directly proportional to the size of its data. Let N denote the number of elements in the sequence to sum.

doubles are always the same size, which makes sum's running time O(1)×N = O(N).

int (formerly known as long) is arbitary-length. Let M denote the absolute value of the largest sequence element. Then sum's worst-case running time is lg(M) + lg(2M) + lg(3M) + ... + lg(NM) = N×lg(M) + lg(N!) = O(N log N).

For str (where M = the length of the longest string), the worst-case running time is M + 2M + 3M + ... + NM = M×(1 + 2 + ... + N) = O(N²).

Thus, summing strings would be much slower than summing numbers.

str.join does not allocate any intermediate objects. It preallocates a buffer large enough to hold the joined strings, and copies the string data. It runs in O(N) time, much faster than sum.

回答6:

The Reason Why

@dan04 has an excellent explanation for the costs of using sum on large lists of strings.

The missing piece as to why str is not allowed for sum is that many, many people were trying to use sum for strings, and not many use sum for lists and tuples and other O(n**2) data structures. The trap is that sum works just fine for short lists of strings, but then gets put in production where the lists can be huge, and the performance slows to a crawl. This was such a common trap that the decision was made to ignore duck-typing in this instance, and not allow strings to be used with sum.

回答7:

Edit: Moved the parts about immutability to history.

Basically, its a question of preallocation. When you use a statement such as

sum(["a", "b", "c", ..., ])

and expect it to work similar to a reduce statement, the code generated looks something like

v1 = "" + "a" # must allocate v1 and set its size to len("") + len("a")
v2 = v1 + "b" # must allocate v2 and set its size to len("a") + len("b")
...
res = v10000 + "$" # must allocate res and set its size to len(v9999) + len("$")

In each of these steps a new string is created, which for one might give some copying overhead as the strings are getting longer and longer. But that’s maybe not the point here. What’s more important, is that every new string on each line must be allocated to it’s specific size (which. I don’t know it it must allocate in every iteration of the reduce statement, there might be some obvious heuristics to use and Python might allocate a bit more here and there for reuse – but at several points the new string will be large enough that this won’t help anymore and Python must allocate again, which is rather expensive.

A dedicated method like join, however has the job to figure out the real size of the string before it starts and would therefore in theory only allocate once, at the beginning and then just fill that new string, which is much cheaper than the other solution.

回答8:

I dont know why, but this works!

import operator
def sum_of_strings(list_of_strings):
    return reduce(operator.add, list_of_strings)