ODOO : Run cron at a specific time

问题:

I want to add a cron job that runs at a specific time.

I have added the cron in xml but it has interval_number and interval_type. How to make it run at a specific time of day?

 <record id="ir_cron_module_get_active_sr" model="ir.cron">
                <field name="name">Get Active Srs</field>
                <field eval="True" name="get_active_srs" />
                <!--<field name="user_id" ref="base.user_root" />-->
                <field name="interval_number">1</field>
                <field name="interval_type">days</field>
                <field name="numbercall">-1</field>
                <field eval="False" name="doall" />
                <field eval="'hr.attendance'" name="model" />
                <field eval="'get_active_srs'" name="function" />
                <field eval="'(None,)'" name="args" />
                <field name="priority">1000</field>
         </record>

回答1:

try

<record id="ir_cron_module_get_active_sr" model="ir.cron">
        <field name="name">Get Active Srs</field>
        <field eval="True" name="get_active_srs" />
        <!--<field name="user_id" ref="base.user_root" />-->
        <field name="interval_number">1</field>
        <field name="nextcall" eval="(DateTime.now() + timedelta(days=1)).strftime('%Y-%m-%d 12:00:00')" />
        <field name="interval_type">days</field>
        <field name="numbercall">-1</field>
        <field eval="False" name="doall" />
        <field eval="'hr.attendance'" name="model" />
        <field eval="'get_active_srs'" name="function" />
        <field eval="'(None,)'" name="args" />
        <field name="priority">1000</field>
</record>