How to test static methods which are infact factory methods:
public function hireEmployee(HireEmployeeCommand $command)
{
$username = new EmployeeUsername($command->getUsername());
$firstName = $command->getFirstName();
$lastName = $command->getLastName();
$phoneNumber = new PhoneNumber($command->getPhoneNumber());
$email = new Email($command->getEmail());
$role = new EmployeeRole($command->getRole());
if ($role->isAdmin()) {
$employee = Employee::hireAdmin($username, $firstName, $lastName, $phoneNumber, $email);
} else {
$employee = Employee::hirePollster($username, $firstName, $lastName, $phoneNumber, $email);
}
$this->employeeRepository->add($employee);
}
Here I can't mock the Employee
object, but I can mock the EmployeeRepository::add()
method for the expected employee but then I'm again checking the state of the Employee:
public function it_hires_an_admin()
{
$this->employeeRepository
->add(Argument::that(/** callback for checking state of Employee object */))
->shouldBeCalled();
$this->hireEmployee(
new HireEmployeeCommand(self::USERNAME, 'John', 'Snow', '123456789', 'john@snow.com', EmployeeRole::ROLE_ADMIN)
);
}
I'm aware that again I mocked the repository instead of stub it. But here I'm more interested in employee will be added to the repository instead of how it would be created. Because of that I should mock the repository but I shouldn't care about the state of the Employee
(without Argument::that()
)? Looks reasonable, but then I can't be sure that the created Employee is correct.