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问题:
Is it possible to iterate a vector from the end to the begin?
for (vector<my_class>::iterator i = my_vector.end();
i != my_vector.begin(); /* ?! */ ) {
}
Or is that only possible with something like that:
for (int i = my_vector.size() - 1; i >= 0; --i) {
}
回答1:
Well, the best way is:
for (vector<my_class>::reverse_iterator i = my_vector.rbegin();
i != my_vector.rend(); ++i ) {
}
rbegin()/rend() especically designed for that purpose. (And yes, incrementing a reverse_interator moves it backward)
Now, in theory, your method (using begin/end & --i
) would work, vector's iterator being bidirectional, But remember, end() isn't the last element -- it's one beyond the last element, so you'd have to decrement first, and you are done when you reach begin() -- but you still have to do your processing.
vector<my_class>::iterator i = my_vector.end();
while (i != my_vector.begin())
{
--i;
/*do stuff */ )
}
UPDATE: I was apparently too aggressive in re-writing the for() loop into a while loop. (The important part is the the --i
is at the beginning.)
回答2:
If you have C++11
, you can make use of auto
.
for (auto it = my_vector.rbegin(); it != my_vector.rend(); ++it)
{
}
回答3:
The well-established "pattern" for reverse-iterating through closed-open ranges looks as follows
// Iterate over [begin, end) range in reverse
for (iterator = end; iterator-- != begin; ) {
// Process `*iterator`
}
or, if you prefer,
// Iterate over [begin, end) range in reverse
for (iterator = end; iterator != begin; ) {
--iterator;
// Process `*iterator`
}
This pattern is usable, for example, for reverse-indexing an array using an unsigned index
int array[N];
...
// Iterate over [0, N) range in reverse
for (unsigned i = N; i-- != 0; ) {
array[i]; // <- process it
}
(People unfamiliar with this pattern often insist on using signed integer types for array indexing specifically because they incorrectly believe that unsigned types prevent reverse indexing)
It can be used for iterating over an array using a "sliding pointer" technique
// Iterate over [array, array + N) range in reverse
for (int *p = array + N; p-- != array; ) {
*p; // <- process it
}
or it can be used for reverse-iteration over a vector using an ordinary (not reverse) iterator
for (vector<my_class>::iterator i = my_vector.end(); i-- != my_vector.begin(); ) {
*i; // <- process it
}
回答4:
User rend() / rbegin()
iterators:
for (vector<myclass>::reverse_iterator it = myvector.rbegin(); it != myvector.rend(); it++)
回答5:
template<class It>
std::reverse_iterator<It> reversed( It it ) {
return std::reverse_iterator<It>(std::forward<It>(it));
}
Then:
for( auto rit = reversed(data.end()); rit != reversed(data.begin()); ++rit ) {
std::cout << *rit;
Alternatively in C++14 just do:
for( auto rit = std::rbegin(data); rit != std::rend(data); ++rit ) {
std::cout << *rit;
In C++03/11 most standard containers have a .rbegin()
and .rend()
method as well.
Finally, you can write the range adapter backwards
as follows:
namespace adl_aux {
using std::begin; using std::end;
template<class C>
decltype( begin( std::declval<C>() ) ) adl_begin( C&& c ) {
return begin(std::forward<C>(c));
}
template<class C>
decltype( end( std::declval<C>() ) ) adl_end( C&& c ) {
return end(std::forward<C>(c));
}
}
template<class It>
struct simple_range {
It b_, e_;
simple_range():b_(),e_(){}
It begin() const { return b_; }
It end() const { return e_; }
simple_range( It b, It e ):b_(b), e_(e) {}
template<class OtherRange>
simple_range( OtherRange&& o ):
simple_range(adl_aux::adl_begin(o), adl_aux::adl_end(o))
{}
// explicit defaults:
simple_range( simple_range const& o ) = default;
simple_range( simple_range && o ) = default;
simple_range& operator=( simple_range const& o ) = default;
simple_range& operator=( simple_range && o ) = default;
};
template<class C>
simple_range< decltype( reversed( adl_aux::adl_begin( std::declval<C&>() ) ) ) >
backwards( C&& c ) {
return { reversed( adl_aux::adl_end(c) ), reversed( adl_aux::adl_begin(c) ) };
}
and now you can do this:
for (auto&& x : backwards(ctnr))
std::cout << x;
which I think is quite pretty.
回答6:
Use reverse iterators and loop from rbegin()
to rend()
回答7:
use this code
//print the vector element in reverse order by normal iterator.
cout <<"print the vector element in reverse order by normal iterator." <<endl;
vector<string>::iterator iter=vec.end();
--iter;
while (iter != vec.begin())
{
cout << *iter << " ";
--iter;
}