从日期的数组获取最新的日期从日期的数组获取最新的日期(Get most recent date fr

下面我有日期的数组

array(5) { 
    [0]=> string(19) "2012-06-11 08:30:49" 
    [1]=> string(19) "2012-06-07 08:03:54" 
    [2]=> string(19) "2012-05-26 23:04:04" 
    [3]=> string(19) "2012-05-27 08:30:00" 
    [4]=> string(19) "2012-06-08 08:30:55" 
}

并想知道最近的日期为：最接近今天的日期。

我怎样才能做到这一点？

Answer 1:

做一个循环，将值转换为日期，存储最新的，在变种。

$mostRecent= 0;
foreach($dates as $date){
  $curDate = strtotime($date);
  if ($curDate > $mostRecent) {
     $mostRecent = $curDate;
  }
}

类似的东西...你如果想最近在今天之前的想法：

$mostRecent= 0;
$now = time();
foreach($dates as $date){
  $curDate = strtotime($date);
  if ($curDate > $mostRecent && $curDate < $now) {
     $mostRecent = $curDate;
  }
}

Answer 2:

使用max() array_map()和strtotime()

$max = max(array_map('strtotime', $arr));
echo date('Y-m-j H:i:s', $max); // 2012-06-11 08:30:49

Answer 3:

按日期排序的数组，然后获取数组的前值。

$dates = array(5) { /** omitted to keep code compact */ }
$dates = array_combine($dates, array_map('strtotime', $dates));
arsort($dates);
echo $dates[0];

Answer 4:

$dates = [
    "2012-06-11 08:30:49" 
    ,"2012-06-07 08:03:54" 
    ,"2012-05-26 23:04:04" 
    ,"2012-05-27 08:30:00" 
    ,"2012-06-08 08:30:55" 
];
echo date("Y-m-d g:i:s",max(array_map('strtotime',$dates)));

Answer 5:

这就是我的变种。它的工作原理与日期在未来。

$Dates = array( 
    "2012-06-11 08:30:49", 
    "2012-06-07 08:03:54", 
    "2012-05-26 23:04:04",
    "2012-05-27 08:30:00",
    "2012-06-08 08:30:55",
    "2012-06-12 07:45:45"
);
$CloseDate = array();
$TimeNow = time();
foreach ($Dates as $Date) {
  $DateToCompare = strtotime($Date);
  $Diff = $TimeNow - $DateToCompare;
  if ($Diff < 0) $Diff *= -1;
  if (count($CloseDate) == 0) {
    $CloseDate['Date'] = $Date;
    $CloseDate['Diff'] = $Diff;
    continue;
  }
  if ($Diff < $CloseDate['Diff']) {
    $CloseDate['Date'] = $Date;
    $CloseDate['Diff'] = $Diff;
  }
}

var_dump($CloseDate);

Answer 6:

我相信，以下是找到最近的日期最短的代码。你可以改变它找到最近日期的索引，找到最近的将来或过去。

$Dates = array( 
"2012-06-11 08:30:49", 
"2012-06-07 08:03:54", 
"2012-05-26 23:04:04",
"2012-05-27 08:30:00",
"2012-06-08 08:30:55",
"2012-06-22 07:45:45"
);

$close_date = current($Dates);
foreach($Dates as $date)
    if( abs(strtotime('now') - strtotime($date)) < abs(strtotime('now') - strtotime($close_date)))
        $close_date = $date;

echo $close_date;

Answer 7:

这里是我的建议：

$most_recent = 0;

foreach($array as $key => $date){
    if( strtotime($date) < strtotime('now') && strtotime($date) > strtotime($array[$most_recent]) ){
        $most_recent = $key;
    }
}

print $array[$most_recent]; //prints most recent day

Answer 8:

$arrayy = array(
    "2012-06-11 08:30:49","2012-06-07 08:03:54","2012-05-26 23:04:04",
    "2012-05-27 08:30:00","2012-06-08 08:30:55" 
);

function getMostRecent($array){
    $current = date("Y-m-d h:i:s");
    $diff1 = NULL;
    $recent = NULL;
    foreach($array as $date){
        if($diff = strcmp($current,$date)){
            if($diff1 == NULL){
                $diff1 = $diff;
                $recent = $date;
            }
            else{
                if($diff < $diff1){
                    $diff1 = $diff;
                    $recent = $date;
                }
            }
        }
    }
    return $recent;
}

Answer 9:

试试这个：

public function getLargerDate(array $datas) {
    $newDates = array();
    foreach($datas as $data){
        $newDates[strtotime($data)] = $data;
    }
    return $newDates[max(array_keys($newDates))];
}

Answer 10:

试试这个工程100％

function getRecentDate($date_list,$curDate){
$curDate = strtotime($curDate); 
    $mostRecent = array();
    foreach($date_list as $date){                                             
       $diff = strtotime($date)-$curDate;
       if($diff>0){
        $mostRecent[$diff] = $date;
       }
    }   
    if(!empty($mostRecent)){
        ksort($mostRecent);            
        $mostRecent_key = key($mostRecent);
        if($mostRecent_key){
            return $mostRecent[$mostRecent_key];
        }
    }else{
        return false;
    }
}
$date_list = array('15-05-2015','14-01-2015','18-03-2015','20-10-2016','12-12-2014','12-12-2015');
$curDate = '14-01-2015';    
$get_recent = getRecentDate($date_list,$curDate);
if($get_recent){
    echo $get_recent;
}else{
    echo 'No recent date exists';
}

Answer 11:

$DatesList = array( '2015-05-19', '2015-09-17', '2015-09-24', '2015-10-02', '2015-10-23', '2015-11-12', '2015-12-25' );

$counter = 0; 
$currentDate = date("Y-m-d");
foreach ($DatesList as $dates)
{
    if($dates >= $currentDate)
    {
        $storeDates[$counter] = $dates;
        $counter++;
    }
}
$closestDate = current($storeDates);
echo $closestDate;

文章来源: Get most recent date from an array of dates