get all the images from a folder in php

问题:

I am using WordPress. I have an image folder like mytheme/images/myimages.

I want to retrieve all the images name from the folder myimages

Please advice me, how can I get images name.

回答1:

try this

$directory = "mytheme/images/myimages";
$images = glob($directory . "/*.jpg");

foreach($images as $image)
{
  echo $image;
}

回答2:

you can do it simply with PHP opendir function.

example:

$handle = opendir(dirname(realpath(__FILE__)).'/pictures/');
while($file = readdir($handle)){
  if($file !== '.' && $file !== '..'){
    echo '<img src="pictures/'.$file.'" border="0" />';
  }
}

回答3:

$dir = "mytheme/images/myimages";
$dh  = opendir($dir);
while (false !== ($filename = readdir($dh))) {
    $files[] = $filename;
}
$images=preg_grep ('/\.jpg$/i', $files);

Very fast because you only scan the needed directory.

回答4:

Check if exist, put all files in array, preg grep all JPG files, echo new array For all images could try this:

$images=preg_grep('/\.(jpg|jpeg|png|gif)(?:[\?\#].*)?$/i', $files);


if ($handle = opendir('/path/to/folder')) {

    while (false !== ($entry = readdir($handle))) {
        $files[] = $entry;
    }
    $images=preg_grep('/\.jpg$/i', $files);

    foreach($images as $image)
    {
    echo $image;
    }
    closedir($handle);
}

回答5:

This answer is specific for WordPress:

$base_dir = trailingslashit( get_stylesheet_directory() );
$base_url = trailingslashit( get_stylesheet_directory_uri() );

$media_dir = $base_dir . 'yourfolder/images/';
$media_url = $hase_url . 'yourfolder/images/';

$image_paths = glob( $media_dir . '*.jpg' );
$image_names = array();
$image_urls = array();

foreach ( $image_paths as $image ) {
    $image_names[] = str_replace( $media_dir, '', $image );
    $image_urls[] = str_replace( $media_dir, $media_url, $image );
}

// --- You now have:

// $image_paths ... list of absolute file paths 
// e.g. /path/to/wordpress/wp-content/uploads/yourfolder/images/sample.jpg

// $image_urls ... list of absolute file URLs 
// e.g. http://example.com/wp-content/uploads/yourfolder/images/sample.jpg

// $image_names ... list of filenames only
// e.g. sample.jpg

Here are some other settings that will give you images from other places than the child theme. Just replace the first 2 lines in above code with the version you need:

From Uploads directory:

// e.g. /path/to/wordpress/wp-content/uploads/yourfolder/images/sample.jpg
$upload_path = wp_upload_dir();
$base_dir = trailingslashit( $upload_path['basedir'] );
$base_url = trailingslashit( $upload_path['baseurl'] );

From Parent-Theme

// e.g. /path/to/wordpress/wp-content/themes/parent-theme/yourfolder/images/sample.jpg
$base_dir = trailingslashit( get_template_directory() );
$base_url = trailingslashit( get_template_directory_uri() );

From Child-Theme

// e.g. /path/to/wordpress/wp-content/themes/child-theme/yourfolder/images/sample.jpg
$base_dir = trailingslashit( get_stylesheet_directory() );
$base_url = trailingslashit( get_stylesheet_directory_uri() );

回答6:

when you want to get all image from folder then use glob() built in function which help to get all image . But when you get all then sometime need to check that all is valid so in this case this code help you. this code will also check that it is image

  $all_files = glob("mytheme/images/myimages/*.*");
  for ($i=0; $i<count($all_files); $i++)
    {
      $image_name = $all_files[$i];
      $supported_format = array('gif','jpg','jpeg','png');
      $ext = strtolower(pathinfo($image_name, PATHINFO_EXTENSION));
      if (in_array($ext, $supported_format))
          {
            echo '<img src="'.$image_name .'" alt="'.$image_name.'" />'."<br /><br />";
          } else {
              continue;
          }
    }

for more information

PHP Manual

回答7:

Here is my some code

$dir          = '/Images';
$ImagesA = Get_ImagesToFolder($dir);
print_r($ImagesA);

function Get_ImagesToFolder($dir){
    $ImagesArray = [];
    $file_display = [ 'jpg', 'jpeg', 'png', 'gif' ];

    if (file_exists($dir) == false) {
        return ["Directory \'', $dir, '\' not found!"];
    } 
    else {
        $dir_contents = scandir($dir);
        foreach ($dir_contents as $file) {
            $file_type = pathinfo($file, PATHINFO_EXTENSION);
            if (in_array($file_type, $file_display) == true) {
                $ImagesArray[] = $file;
            }
        }
        return $ImagesArray;
    }
}

回答8:

//path to the directory to search/scan
        $directory = "";
         //echo "$directory"
        //get all files in a directory. If any specific extension needed just have to put the .extension
        //$local = glob($directory . "*"); 
        $local = glob("" . $directory . "{*.jpg,*.gif,*.png}", GLOB_BRACE);
        //print each file name
        echo "<ul>";

        foreach($local as $item)
        {
        echo '<li><a href="'.$item.'">'.$item.'</a></li>';
        }

        echo "</ul>";

回答9:

You can simply show your actual image directory(less secure). By just 2 line of code.

 $dir = base_url()."photos/";

echo"<a href=".$dir.">Photo Directory</a>";