sqlite3.ProgrammingError: Incorrect number of bind

问题:

def insert(array):
    connection=sqlite3.connect(\'images.db\')
    cursor=connection.cursor()
    cnt=0
    while cnt != len(array):
            img = array[cnt]
            print(array[cnt])
            cursor.execute(\'INSERT INTO images VALUES(?)\', (img))
            cnt+= 1
    connection.commit()
    connection.close()

I cannot figure out why this is giving me the error, The actual string I am trying to insert is 74 chars long, it\'s: \"/gifs/epic-fail-photos-there-i-fixed-it-aww-man-the-tire-pressures-low.gif\"

I\'ve tried to str(array[cnt]) before inserting it, but the same issue is happening, the database only has one column, which is a TEXT value.

I\'ve been at it for hours and I cannot figure out what is going on.

回答1:

You need to pass in a sequence, but you forgot the comma to make your parameters a tuple:

cursor.execute(\'INSERT INTO images VALUES(?)\', (img,))

Without the comma, (img) is just a grouped expression, not a tuple, and thus the img string is treated as the input sequence. If that string is 74 characters long, then Python sees that as 74 separate bind values, each one character long.

>>> len(img)
74
>>> len((img,))
1

If you find it easier to read, you can also use a list literal:

cursor.execute(\'INSERT INTO images VALUES(?)\', [img])

回答2:

cursor.execute(sql,array)

Only takes two arguments.
It will iterate the \"array\"-object and match ? in the sql-string.
(with sanity checks to avoid sql-injection)