I need to fire a function when a Backbone.js view is removed. I guess something like a de-constructor. The code below is a snippet I wrote; I know it won't work. However, I do remember seeing in the past a video tutorial on how to write a function that does this. The reason I need to run a de-constructing function is to clear the interval set inside a view when the view is removed.
ViewWeather = Backbone.View.extend({
interval: setInterval(function() {console.log('interval fire');}, 1000),
// made up function
deconstructor: function () {
// if the view is removed
clearInterval(this.interval);
}
});
var viewweather = new ViewWeather();
This blog post should give you some better info
http://lostechies.com/derickbailey/2011/09/15/zombies-run-managing-page-transitions-in-backbone-apps/
most notable parts
Backbone.View.prototype.close = function(){
this.remove();
this.unbind();
if (this.onClose){
this.onClose();
}
}
and then
MyView = Backbone.View.extend({
initialize: function(){
this.model.bind("change", this.render, this);
},
render: function(){ ... },
onClose: function(){
this.model.unbind("change", this.render);
}
});
i am not sure if I understand you correctly, but the approach you are showing seems correct:
dispose: function(id) {
clearInterval(this.interval);
this.remove();
}
you are going to have to call dispose yourself, by e.g. an event:
initialize: function(opts) {
router.bind('route:leave', this.dispose, this);
},
edit after comments: this should work to overload remove
remove: function() {
clearInterval(this.interval);
Backbone.View.prototype.remove.call(this);
}