process.stdout.clearLine()
deletes latest line. How can I delete all lines from stdout
?
var out = process.stdout;
out.write("1\n"); // prints `1` and new line
out.write("2"); // prints `2`
setTimeout(function () {
process.stdout.clearLine(); // clears the latest line (`2`)
out.cursorTo(0); // moves the cursor at the beginning of line
out.write("3"); // prints `3`
out.write("\n4"); // prints new line and `4`
console.log();
}, 1000);
The output is:
1
3
4
I want to delete all lines from stdout
instead of latest line, so the output will be:
3
4
dont know if this helps you try this code:
var out = process.stdout;
var numOfLinesToClear = 0;
out.write("1\n"); // prints `1` and new line
++numOfLinesToClear;
out.write("2\n");
++numOfLinesToClear;
process.stdout.moveCursor(0,-numOfLinesToClear); //move the cursor to first line
setTimeout(function () {
process.stdout.clearLine();
out.cursorTo(0); // moves the cursor at the beginning of line
out.write("3"); // prints `3`
out.write("\n4"); // prints new line and `4`
console.log();
}, 1000);
You can try this one also; process.stdout.write('\u001B[2J\u001B[0;0f');
this has the same effect of issuing the clear
command on the command line! Maybe that helps!
try this:-
var x = 1, y = 2;
process.stdout.write(++x + "\n" + (++y))
function status() {
process.stdout.moveCursor(0, -2) // moving two lines up
process.stdout.cursorTo(0) // then getting cursor at the begining of the line
process.stdout.clearScreenDown() // clearing whatever is next or down to cursor
process.stdout.write(++x + "\n" + (++y))
}
setInterval(status, 1000)