Uploading image in ASP.NET MVC

问题:

I have a Upload form and I want to pass my information such as an Image and some other field but I don't know how can I upload Image ..

this is my controller code :

[HttpPost]
        public ActionResult Create(tblPortfolio tblportfolio)
        {
            if (ModelState.IsValid)
            {
                db.tblPortfolios.AddObject(tblportfolio);
                db.SaveChanges();
                return RedirectToAction("Index");  
            }

            return View(tblportfolio);
        }

And this is my view code :

@model MyApp.Models.tblPortfolio

<h2>Create</h2>

@using (Html.BeginForm(null, null, FormMethod.Post, new { enctype = "multipart/form-data" }))
{
    @Html.ValidationSummary(true)
    <fieldset>
        <legend>tblPortfolio</legend>

        <div class="editor-label">
            @Html.LabelFor(model => model.Title)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.Title)
            @Html.ValidationMessageFor(model => model.Title)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.ImageFile)
        </div>
        <div class="editor-field">
            @Html.TextBoxFor(model => model.ImageFile, new { type = "file" })
            @Html.ValidationMessageFor(model => model.ImageFile)
        </div>

        <div class="editor-label">
            @Html.LabelFor(model => model.Link)
        </div>
        <div class="editor-field">
            @Html.EditorFor(model => model.Link)
            @Html.ValidationMessageFor(model => model.Link)
        </div>

        <p>
            <input type="submit" value="Create" />
        </p>
    </fieldset>
}

Now I don't know how can I upload Image and save it on server .. how can I set Image name by Guid.NewGuid(); ? Or how can I set Image Path ?

回答1:

Firstly, you'll need to change your view to include the following:

<input type="file" name="file" />

Then you'll need to change your post ActionMethod to take a HttpPostedFileBase, like so:

[HttpPost]
public ActionResult Create(tblPortfolio tblportfolio, HttpPostedFileBase file)
{
    //you can put your existing save code here
    if (file != null && file.ContentLength > 0) 
    {
        //do whatever you want with the file
    }
}

回答2:

You can get it from Request using Request.Files Collection, In case of single file upload just read from the first index using Request.Files[0]:

[HttpPost]
public ActionResult Create(tblPortfolio tblportfolio) 
{
 if(Request.Files.Count > 0)
 {
 HttpPostedFileBase file = Request.Files[0];
 if (file != null) 
 { 
  // business logic here  
 }
 } 
}

In case of Multiple files uploading, you have to iterate on the Request.Files collection:

[HttpPost] 
public ActionResult Create(tblPortfolio tblportfolio)
{ 
 for(int i=0; i < Request.Files.Count; i++)
 {
   HttpPostedFileBase file = Request.Files[i];
   if (file != null)
   {
    // Do something here
   }
 }
}

If you want to upload file without page refresh via ajax then you can use this article which uses jquery plugin