My Xml looks like:
<root>
<foo location="bar"/>
<foo location="in" flag="123"/>
<foo location="pak"/>
<foo location="us" flag="256"/>
<foo location="blah"/>
</root>
For foo xml element flag is optional attribute.
And when I say:
<xmlproperty file="${base.dir}/build/my.xml" keeproot="false"/>
<echo message="foo(location) : ${foo(location)}"/>
prints all locations :
foo(location) : bar,in,pak,us,blah
Is there a way to get locations only if flag is set to some value?
Is there a way to get locations only if flag is set to some value?
Not with xmlproperty
, no, as that will always conflate values that have the same tag name. But xmltask can do what you need as it supports the full power of XPath:
<taskdef name="xmltask" classname="com.oopsconsultancy.xmltask.ant.XmlTask">
<classpath path="xmltask.jar" />
</taskdef>
<xmltask source="${base.dir}/build/my.xml">
<copy path="/root/foo[@flag='123' or @flag='256']/@location"
property="foo.location"
append="true" propertySeparator="," />
</xmltask>
<echo>${foo.location}</echo><!-- prints in,us -->
If you absolutely cannot use third-party tasks then I'd probably approach the problem by using a simple XSLT to extract just the bits of the XML that you do want into another file:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:param name="targetFlag" />
<xsl:template name="ident" match="@*|node()">
<xsl:copy><xsl:apply-templates select="@*|node()" /></xsl:copy>
</xsl:template>
<xsl:template match="foo">
<xsl:if test="@flag = $targetFlag">
<xsl:call-template name="ident" />
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Call this with the xslt
task
<xslt in="${base.dir}/build/my.xml" out="filtered.xml" style="extract.xsl">
<param name="targetFlag" expression="123" />
</xslt>
This will create filtered.xml
containing just
<root>
<foo location="in" flag="123"/>
</root>
(modulo changes in whitespace) and you can load this using xmlproperty in the normal way.