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问题:
As suggested by @Silencer, I used the code he posted here to draw contours around the numbers in my image.
At some point, working with numbers like 0,6,8,9
I saw that their inside contours (the circles) are being filled as well.
How can I prevent this ? Is there a min/max area of action to set for cv2.drawContours() so I can exclude the inner area ?
I tried to pass cv2.RETR_EXTERNAL
but with this parameter only the whole external area is considered.
The code is this (again, thanks Silencer. Was searching for this for months..):
import numpy as np
import cv2
im = cv2.imread('imgs\\2.png')
imgray = cv2.cvtColor(im, cv2.COLOR_BGR2GRAY)
ret, thresh = cv2.threshold(imgray, 127, 255, 0)
image, contours, hierarchy = cv2.findContours(thresh, cv2.RETR_TREE, cv2.CHAIN_APPROX_SIMPLE)
#contours.sort(key=lambda x: int(x.split('.')[0]))
for i, cnts in enumerate(contours):
## this contour is a 3D numpy array
cnt = contours[i]
res = cv2.drawContours(im, [cnt], 0, (255, 0, 0), 1)
cv2.imwrite("contours.png", res)
'''
## Method 1: crop the region
x,y,w,h = cv2.boundingRect(cnt)
croped = res[y:y+h, x:x+w]
cv2.imwrite("cnts\\croped{}.png".format(i), croped)
'''
## Method 2: draw on blank
# get the 0-indexed coords
offset = cnt.min(axis=0)
cnt = cnt - cnt.min(axis=0)
max_xy = cnt.max(axis=0) + 1
w, h = max_xy[0][0], max_xy[0][1]
# draw on blank
canvas = np.ones((h, w, 3), np.uint8) * 255
cv2.drawContours(canvas, [cnt], -1, (0, 0, 0), -1)
#if h > 15 and w < 60:
cv2.imwrite("cnts\\canvas{}.png".format(i), canvas)
The main image on which I am working..
Thanks
UPDATE
I implemented Fiver answer below and this is the result:
import cv2
import numpy as np
img = cv2.imread('img.png')
img_hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
img_v = img_hsv[:, :, 2]
ret, thresh = cv2.threshold(~img_v, 127, 255, 0)
image, contours, hierarchy = cv2.findContours(thresh, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
for i, c in enumerate(contours):
tmp_img = np.zeros(img_v.shape, dtype=np.uint8)
res = cv2.drawContours(tmp_img, [c], -1, 255, cv2.FILLED)
tmp_img = np.bitwise_and(tmp_img, ~img_v)
ret, inverted = cv2.threshold(tmp_img, 127, 255, cv2.THRESH_BINARY_INV)
cnt = contours[i]
x, y, w, h = cv2.boundingRect(cnt)
cropped = inverted[y:y + h, x:x + w]
cv2.imwrite("roi{}.png".format(i), cropped)
回答1:
To draw the char
without filled the closed inner regions:
find the contours on the threshed binary image with hierarchy.
find the outer contours that don't have inner objects (by flag hierarchyi).
for each outer contour:
3.1 fill it(maybe need check whether needed);
3.2 then iterate in it's inner children contours, fill then with other color(such as inversed color).
combine with the crop code, crop them.
- maybe you need sort them, resplit them, normalize them.
- maybe, now you can do ocr with the trained model.
FindContours, refill the inner closed regions.
Combine with this answer Copy shape to blank canvas (OpenCV, Python), do more steps, maybe you can get this or better:
The core code to refill
the inner closed regions is as follow:
#!/usr/bin/python3
# 2018.01.14 09:48:15 CST
# 2018.01.15 17:56:32 CST
# 2018.01.15 20:52:42 CST
import numpy as np
import cv2
img = cv2.imread('img02.png')
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
## Threshold
ret, threshed = cv2.threshold(gray, 127, 255, cv2.THRESH_BINARY_INV|cv2.THRESH_OTSU)
## FindContours
cnts, hiers = cv2.findContours(threshed, cv2.RETR_TREE, cv2.CHAIN_APPROX_SIMPLE)[-2:]
canvas = np.zeros_like(img)
n = len(cnts)
hiers = hiers[0]
for i in range(n):
if hiers[i][3] != -1:
## If is inside, the continue
continue
## draw
cv2.drawContours(canvas, cnts, i, (0,255,0), -1, cv2.LINE_AA)
## Find all inner contours and draw
ch = hiers[i][2]
while ch!=-1:
print(" {:02} {}".format(ch, hiers[ch]))
cv2.drawContours(canvas, cnts, ch, (255,0,255), -1, cv2.LINE_AA)
ch = hiers[ch][0]
cv2.imwrite("001_res.png", canvas)
Run this code with this image:
You will get:
Of course, this is for two hierarchies. I haven't test for more than two. You who need can do test by yourself.
Update:
Notice in different OpenCVs, the cv2.findContours
return different values. To keep code executable, we can just get the last two returned values use: cnts, hiers = cv2.findContours(...)[-2:]
In OpenCV 3.4:
In OpenCV 4.0:
回答2:
Since you already have a mask from your threshold step, you can also use it to bitwise_and
against the drawn contour:
import cv2
import numpy as np
import matplotlib.pyplot as plt
img = cv2.imread('drawn_chars.png')
img_hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
img_v = img_hsv[:, :, 2]
ret, thresh = cv2.threshold(~img_v, 127, 255, 0)
image, contours, hierarchy = cv2.findContours(
thresh,
cv2.RETR_EXTERNAL,
cv2.CHAIN_APPROX_SIMPLE
)
for c in contours:
tmp_img = np.zeros(img_v.shape, dtype=np.uint8)
cv2.drawContours(tmp_img, [c], -1, 255, cv2.FILLED)
tmp_img = np.bitwise_and(tmp_img, ~img_v)
plt.figure(figsize=(16, 2))
plt.imshow(tmp_img, cmap='gray')
I've inverted the image so the contours are white and I left out the cropping as you already solved that. Here is the result on one of the "O" characters:
回答3:
Full code...
This will not sort the images.
import numpy as np
import cv2
im = cv2.imread('imgs\\1.png')
imgray = cv2.cvtColor(im, cv2.COLOR_BGR2GRAY)
## Threshold
ret, threshed = cv2.threshold(imgray, 127, 255, cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)
## FindContours
image, cnts, hiers = cv2.findContours(threshed, cv2.RETR_TREE, cv2.CHAIN_APPROX_SIMPLE)
canvas = np.zeros_like(im)
n = len(cnts)
hiers = hiers[0]
for i, imgs in enumerate(cnts):
cnt = cnts[i]
res = cv2.drawContours(im, [cnt], 0, (0, 0, 0), -1)
x, y, w, h = cv2.boundingRect(cnt)
croped = res[y:y + h, x:x + w]
if h > 10:
cv2.imwrite("out\\croped{}.png".format(i), croped)
cv2.imshow('i', croped)
cv2.waitKey(0)
for i, value in enumerate(cnts):
## this contour is a 3D numpy array
cnt = cnts[i]
res = cv2.drawContours(im, [cnt], 0, (0, 0, 0), -1)
# cv2.imwrite("out\\contours{}.png".format(i), res)
## Find all inner contours and draw
ch = hiers[i][2]
while ch != -1:
print(" {:02} {}".format(ch, hiers[ch]))
res1 = cv2.drawContours(im, cnts, ch, (255, 255, 255), -1)
ch = hiers[ch][0]
x, y, w, h = cv2.boundingRect(cnt)
croped = res[y:y + h, x:x + w]
if h > 10:
cv2.imwrite("out\\croped{}.png".format(i), croped)
Any correction is accepted.
回答4:
This will do definetively the job...
import cv2
import os
import numpy as np
img = cv2.imread("image.png")
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
retval, thresholded = cv2.threshold(gray, 0, 255, cv2.THRESH_BINARY_INV | cv2.THRESH_OTSU)
medianFiltered = cv2.medianBlur(thresholded, 3)
_, contours, hierarchy = cv2.findContours(medianFiltered, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
contour_list = []
for contour in contours:
area = cv2.contourArea(contour)
if area > 80:
contour_list.append(contour)
numbers = cv2.drawContours(img, contour_list, -1, (0, 0, 0), 2)
cv2.imshow('i', numbers)
cv2.waitKey(0)
sorted_ctrs = sorted(contours, key=lambda ctr: cv2.boundingRect(ctr)[0])
for i, cnts in enumerate(contours):
cnt = contours[i]
x, y, w, h = cv2.boundingRect(cnt)
croped = numbers[y:y + h, x:x + w]
h, w = croped.shape[:2]
print(h, w)
if h > 15:
cv2.imwrite("croped{}.png".format(i), croped)
回答5:
This is conceptually similar to Fivers answer, just that bitwise_and occurs outside the for loop and perhaps is better in terms of performance. Source code is in C++ for those looking for C++ answer for this problem.
int thWin = 3;
int thOffset = 1;
cv::adaptiveThreshold(image, th, 255, cv::ADAPTIVE_THRESH_MEAN_C, cv::THRESH_BINARY_INV, thWin, thOffset);
int minMoveCharCtrArea = 140;
std::vector<std::vector<cv::Point> > contours;
std::vector<cv::Vec4i> hierarchy;
cv::findContours(th.clone(), contours, hierarchy, cv::RETR_LIST, cv::CHAIN_APPROX_SIMPLE);
cv::Mat filtImg = cv::Mat::zeros(img.rows, img.cols, CV_8UC1 );
for (int i = 0; i< contours.size(); ++i) {
int ctrArea = cv::contourArea(contours[i]);
if (ctrArea > minMoveCharCtrArea) {
cv::drawContours(filtImg, contours, i, 255, -1);
}
}
cv::bitwise_and(th, filtImg, filtImg);
Remember to clone the image (for python it should be copy) when passing source image argument to findContours, since findContours modifies the original image. I reckon later versions of opencv (perhaps opencv3 +) don't require cloning.