I am a Ruby starter. I found both of these are quite similar (in output), but i couldn't understand the difference in the below context. For example, I have a class
class Say
def self.hello
puts "hello"
end
end
and can be extended like this
class << Say
def hi
puts "hi"
end
end
and also like this
Say.class_eval do
def self.bye
puts "bye"
end
end
When should I use <<
and when class_eval
?
class_eval
doesn't really have anything to do with class << className
.
A.class_eval do
...
end
is equivalent to
class A
...
end
with a few differences. class_eval uses a block (or a string, but ignoring that for the moment) which means it closes over the containing lexical scope. In other words you can use local variables from the surrounding scope. The common class block introduces a brand new scope. Likewise you can create the block and pass it to many different class_eval's, and the body of the block will be executed in the context of the class you are calling class_eval on.
class << className
opens the singleton class of className
, allowing you to define class methods.
class << A
def foo
...
end
end
Is the same as
def A.foo
...
end
Note that they are oly class methods if A happens to be a class (almost) all objects in ruby have singleton classes and you can define methods for them using either of those two syntaxes. The advantage of class << obj
is mainly if you're defining many singleton methods in one go.
As already said class_eval has really not much to do with
class <<self
even if they seem to do the same thing in your example (while the effect is similar it does not do the same, there are subtle differences).
Here is another example where the usage of the second form is far more clearer:
class A
end
a = A.new
b = A.new
class <<b
def say_hi
puts "Hi !"
end
end
b.say_hi # will print "Hi !"
a.say_hi # will raise an undefined method
a and b are both objects of the same class A but we added a method to the metaclass of b so the method say_hi is only available to the b object.