Shell script to capture Process ID and kill it if

问题:

This question already has an answer here:

• Find and kill a process in one line using bash and regex 22 answers

I tried this code and it is not working

#!/bin/sh

#Find the Process ID for syncapp running instance

PID=`ps -ef | grep syncapp 'awk {print $2}'`

if [[ -z "$PID" ]] then
Kill -9 PID
fi

It is showing a error near awk.

Any suggestions please.

回答1:

Actually the easiest way to do that would be to pass kill arguments like below:

ps -ef | grep your_process_name | grep -v grep | awk '{print $2}' | xargs kill

Hope it helps.

回答2:

This works good for me.

PID=`ps -eaf | grep syncapp | grep -v grep | awk '{print $2}'`
if [[ "" !=  "$PID" ]]; then
  echo "killing $PID"
  kill -9 $PID
fi

回答3:

I use the command pkill for this:

NAME
       pgrep, pkill - look up or signal processes based on name and 
       other attributes

SYNOPSIS
       pgrep [options] pattern
       pkill [options] pattern

DESCRIPTION
       pgrep looks through the currently running processes and lists 
       the process IDs which match the selection criteria to stdout.
       All the criteria have to match.  For example,

              $ pgrep -u root sshd

       will only list the processes called sshd AND owned by root.
       On the other hand,

              $ pgrep -u root,daemon

       will list the processes owned by root OR daemon.

       pkill will send the specified signal (by default SIGTERM) 
       to each process instead of listing them on stdout.

If your code runs via interpreter (java, python, ...) then the name of the process is the name of the interpreter. You need to user the argument --full. This matches against the command name and the arguments.

回答4:

You probably wanted to write

`ps -ef | grep syncapp | awk '{print $2}'`

but I will endorse @PaulR's answer - killall -9 syncapp is a much better alternative.

回答5:

A lot of *NIX systems also have either or both pkill(1) and killall(1) which, allows you to kill processes by name. Using them, you can avoid the whole parsing ps problem.

回答6:

Came across somewhere..thought it is simple and useful

You can use the command in crontab directly ,

* * * * * ps -lf | grep "user" |  perl -ane '($h,$m,$s) = split /:/,$F
+[13]; kill 9, $F[3] if ($h > 1);'

or, we can write it as shell script ,

#!/bin/sh
# longprockill.sh
ps -lf | grep "user" |  perl -ane '($h,$m,$s) = split /:/,$F[13]; kill
+ 9, $F[3] if ($h > 1);'

And call it crontab like so,

* * * * * longprockill.sh

回答7:

#!/bin/sh

#Find the Process ID for syncapp running instance

PID=`ps -ef | grep syncapp 'awk {print $2}'`

if [[ -z "$PID" ]] then
--->    Kill -9 PID
fi

Not sure if this helps, but 'kill' is not spelled correctly. It's capitalized.

Try 'kill' instead.

回答8:

This should kill all processes matching the grep that you are permitted to kill.

-9 means "Kill all processes you can kill".

kill -9 $(ps -ef | grep [s]yncapp | awk '{print $2}')

回答9:

Try the following script:

#!/bin/bash
pgrep $1 2>&1 > /dev/null
if [ $? -eq 0 ]
then
{
    echo " "$1" PROCESS RUNNING "
    ps -ef | grep $1 | grep -v grep | awk '{print $2}'| xargs kill -9
}
else
{
    echo "  NO $1 PROCESS RUNNING"
};fi

回答10:

Kill -9 PID

should be

kill -9 $PID

see the difference?

回答11:

PID=`ps -ef | grep syncapp 'awk {print $2}'`

if [[ -z "$PID" ]] then
**Kill -9 $PID**
fi