Initialize a static final field in the constructor

问题:

public class A 
{    
    private static final int x;

    public A() 
    {
        x = 5;
    }
}

• final means the variable can only be assigned once (in the constructor).
• static means it's a class instance.

I can't see why this is prohibited. Where do those keywords interfere with each other?

回答1:

A constructor will be called each time an instance of the class is created. Thus, the above code means that the value of x will be re-initialized each time an instance is created. But because the variable is declared final (and static), you can only do this

class A {    
    private static final int x;

    static {
        x = 5;
    }
}

But, if you remove static, you are allowed to do this:

class A {    
    private final int x;

    public A() {
        x = 5;
    }
}

OR this:

class A {    
    private final int x;

    {
        x = 5;
    }
}

回答2:

static final variables are initialized when the class is loaded. The constructor may be called much later, or not at all. Also, the constructor will be called multiple times (with each new object ), so the field could no longer be final.

If you need custom logic to initialize your static final field, put that in a static block

回答3:

Think about what happens the second time you instantiate an object. It tries to set it AGAIN, which is expressly prohibited by being a static final. It can only be set one time for the entire class, not instance.

You should set the value when you declare it

private static final x=5;

If you need additional logic, or more complex instantiation, this can be done in a static initializer block.

回答4:

static means that the variable is unique on the application. final means that it should be set only once.

If you set it in your constructor, you allow to set the variable more than once.

Hence you should intialize it directly or propose a static method to initialize it.

回答5:

Final doesn't mean that is has to be initialized in the constructor. Generally this is what is done :

 private static final int x = 5;

static instead means that the variable will be shared through multiple instances of the class. For example :

public class Car {
   static String name;
   public Car(String name) {
      this.name = name;
   }
}

...

Car a = new Car("Volkswagen");
System.out.println(a.name); // Produces Volkswagen

Car b = new Car("Mercedes");
System.out.println(b.name); // Produces Mercedes
System.out.println(a.name); // Produces Mercedes

回答6:

Think about it. You could do this with your code:

A a = new A();
A b = new A(); // Wrong... x is already initialised

The correct ways to initialise x are:

public class A 
{    
    private static final int x = 5;
}

or

public class A 
{    
    private static final int x;

    static
    {
        x = 5;
    }
}

回答7:

    public class StaticFinalExample {
  /*
   * Static final fields should be initialized either in
   * static blocks or at the time of declaration only
   * Reason : They variables are like the utility fields which should be accessible
   * before object creation only once.
   */
  static final int x;

  /*
   * Final variables shuould be initialized either at the time of declaration or
   * in initialization block or constructor only as they are not accessible in static block
   */
  final int y;

  /*
   * Static variables can be initialized either at the time of declaration or
   * in initialization or constructor or static block. Since the default value is given to the
   * static variables by compiler, so it depends on when you need the value
   * depending on that you can initialize the variable appropriately
   * An example of this is shown below in the main method
   */
  static int z;

  static {
    x = 20; // Correct
  }
  {
    y = 40; // Correct
  }
  StaticFinalExample() {
    z = 50; // Correct
  }
  public static void main (String args[]) {
    System.out.println("Before Initialization in Constructor" + z);   // It will print 0
    System.out.println("After Initializtion in Constructor" + new StaticFinalExample().z); // It will print 50
  }
}