I'm trying to convert my sample HTML output into a plain text but I don't know how. I use file_get_contents but the page which I'm trying to convert returns most like the same.
$raw = "http://localhost/guestbook/profiles.php";
$file_converted = file_get_contents($raw);
echo $file_converted;
profiles.php
<html>
<head>
<title>Profiles - GuestBook</title>
<link rel="stylesheet" type="text/css" href="css/style.css">
</head>
<body>
<!-- Some Divs -->
<div id="profile-wrapper">
<h2>Profile</h2>
<table>
<tr>
<td>Name:</td><td> John Dela Cruz</td>
</tr>
<tr>
<td>Age:</td><td>15</td>
</tr>
<tr>
<td>Location:</td><td> SomewhereIn, Asia</td>
</tr>
</table>
</div>
</body>
</html>
Basically, I trying to echo out something like this (plain text, no styles)
Profile
Name: John Dela Cruz
Age: 15
Location: SomewhereIn, Asia
but i don't know how. :-( . Please help me guys , thank you in advance.
EDIT: Since i am only after of the content of the page, no matter if it's styled or just a plain text , is there a way to select only (see code below) using file_get_contents() ?
<h2>Profile</h2>
<table>
<tr>
<td>Name:</td><td> John Dela Cruz</td>
</tr>
<tr>
<td>Age:</td><td>15</td>
</tr>
<tr>
<td>Location:</td><td> SomewhereIn, Asia</td>
</tr>
</table>