C++ convert decimal hours into hours, minutes, and

问题:

I have some number of miles and a speed in MPH that I have converted into the number of hours it takes to travel that distance at that speed. Now I need to convert this decimal number into hours, minutes, and seconds. How do I do this? My best guess right now is:

double time = distance / speed;
int hours = time; // double to integer conversion chops off decimal
int minutes = (time - hours) * 60;
int seconds = (((time - hours) * 60) - minutes) * 60;

Is this right? Is there a better way to do this? Thanks!

回答1:

I don't know c++ functions off the top of my head, however this "psuedocode" should work.

double time = distance / speed;
int hours = time;
double minutesRemainder = (time - hours) * 60;
int minutes = minutesRemainder;
double secondsRemainder = (minutesRemainder - minutes) * 60;
int seconds = secondsRemainder;

Corrected not needing floor.

As far as the comment about it not working for negative times, you can't have a negative distance in physics. I'd say that would be user input error, not coder error!

回答2:

I don't know if this is better...actually I don't know for sure that it is right as I haven't tested it, but I would first convert the hours to the total number of seconds, then convert that back into hours/minutes/seconds. It would look something like:

int totalseconds = time * 3600.0;

// divide by number of seconds in an hour, then round down by casting to an integer.
int hours = totalseconds/3600;

// divide by 60 to get minutes, then mod by 60 to get the number minutes that aren't full hours
int minutes = (totalseconds/60) % 60;  

// use mod 60 to to get number of seconds that aren't full minutes
int seconds = totalseconds % 60;  

回答3:

I'd say you've got it right. :-)

Though I should add, if a method like that Aequitarium Custos has presented is more readable or preferable to you, by all means use that method. Sometimes it's easier to calculate data elements one at a time, and calculate the next one from the one you just calculated, rather than using an absolute formula always beginning from your first datum.

In the end, as long as your math is correct (and I think it is), it's up to you how you want to write the code.

回答4:

a. Check if speed is not 0

b. it is bad programming to put a double into an int IMHO. use floor (assuming time is positive...)

c. if speed and distance are int - the result in time will be wrong...

d. @Aequitarum Custos got it right after the edit...