问题:

I'm attempting to POST to a uri, and send the parameter username=me

Invoke-WebRequest -Uri http://example.com/foobar -Method POST

How do I pass the parameters using the method POST?

回答1:

Put your parameters in a hash table and pass them like this:

$postParams = @{username='me';moredata='qwerty'}
Invoke-WebRequest -Uri http://example.com/foobar -Method POST -Body $postParams

回答2:

For some picky web services, the request needs to have the content type set to JSON and the body to be a JSON string. For example:

Invoke-WebRequest -UseBasicParsing http://example.com/service -ContentType "application/json" -Method POST -Body "{ 'ItemID':3661515, 'Name':'test'}"

or the equivalent for XML, etc.

回答3:

This just works:

$body = @{
 "UserSessionId"="12345678"
 "OptionalEmail"="MyEmail@gmail.com"
} | ConvertTo-Json

$header = @{
 "Accept"="application/json"
 "connectapitoken"="97fe6ab5b1a640909551e36a071ce9ed"
 "Content-Type"="application/json"
} 

Invoke-RestMethod -Uri "http://MyServer/WSVistaWebClient/RESTService.svc/member/search" -Method 'Post' -Body $body -Headers $header | ConvertTo-HTML