你如何执行Oracle的相当于DESCRIBE TABLE
(使用psql的命令)在PostgreSQL的?
Answer 1:
试试这个(在psql
命令行工具):
\d+ tablename
请参阅手册以获得更多信息。
Answer 2:
除了PostgreSQL的方式(\ d“某物”或\ DT“表”或\ DS“序列”等)
SQL标准的方式,如图所示在这里 :
select column_name, data_type, character_maximum_length
from INFORMATION_SCHEMA.COLUMNS where table_name = '<name of table>';
它是由许多数据库引擎的支持。
Answer 3:
如果你想从查询,而不是PSQL获得它,你可以查询目录模式。 这里有一个复杂的查询,做的是:
SELECT
f.attnum AS number,
f.attname AS name,
f.attnum,
f.attnotnull AS notnull,
pg_catalog.format_type(f.atttypid,f.atttypmod) AS type,
CASE
WHEN p.contype = 'p' THEN 't'
ELSE 'f'
END AS primarykey,
CASE
WHEN p.contype = 'u' THEN 't'
ELSE 'f'
END AS uniquekey,
CASE
WHEN p.contype = 'f' THEN g.relname
END AS foreignkey,
CASE
WHEN p.contype = 'f' THEN p.confkey
END AS foreignkey_fieldnum,
CASE
WHEN p.contype = 'f' THEN g.relname
END AS foreignkey,
CASE
WHEN p.contype = 'f' THEN p.conkey
END AS foreignkey_connnum,
CASE
WHEN f.atthasdef = 't' THEN d.adsrc
END AS default
FROM pg_attribute f
JOIN pg_class c ON c.oid = f.attrelid
JOIN pg_type t ON t.oid = f.atttypid
LEFT JOIN pg_attrdef d ON d.adrelid = c.oid AND d.adnum = f.attnum
LEFT JOIN pg_namespace n ON n.oid = c.relnamespace
LEFT JOIN pg_constraint p ON p.conrelid = c.oid AND f.attnum = ANY (p.conkey)
LEFT JOIN pg_class AS g ON p.confrelid = g.oid
WHERE c.relkind = 'r'::char
AND n.nspname = '%s' -- Replace with Schema name
AND c.relname = '%s' -- Replace with table name
AND f.attnum > 0 ORDER BY number
;
这是相当复杂的,但它确实表明你PostgreSQL系统目录中的动力和灵活性,应该让你用自己的方式pg_catalog掌握;-)。 请务必在查询中更改了%s的。 首先是模式,第二个是表名。
Answer 4:
你可以这样做与psql的斜杠命令:
\d myTable describe table
这也适用于其他对象:
\d myView describe view
\d myIndex describe index
\d mySequence describe sequence
来源: faqs.org
Answer 5:
psql的等效的DESCRIBE TABLE
是\d table
。
请参考PostgreSQL手册的PSQL部分的更多细节。
Answer 6:
你可以做一个\d *search pattern *
用星号来查找匹配你感兴趣的搜索模式的表。
Answer 7:
除了命令行\d+ <table_name>
您已经发现了,你也可以使用信息架构来查找列数据,使用info_schema.columns
SELECT *
FROM info_schema.columns
WHERE table_schema = 'your_schema'
AND table_name = 'your_table'
Answer 8:
您可以使用此:
SELECT attname
FROM pg_attribute,pg_class
WHERE attrelid=pg_class.oid
AND relname='TableName'
AND attstattarget <>0;
Answer 9:
使用下面的SQL语句
SELECT DATA_TYPE
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_name = 'tbl_name'
AND COLUMN_NAME = 'col_name'
如果更换tbl_name和COL_NAME,它会显示你寻找的特定coloumn的数据类型。
Answer 10:
查询的这种变化(在其他的答案解释)时为我工作。
SELECT
COLUMN_NAME
FROM
information_schema.COLUMNS
WHERE
TABLE_NAME = 'city';
它在这里描述的细节: http://www.postgresqltutorial.com/postgresql-describe-table/
Answer 11:
在MySQL中,DESCRIBE TABLE_NAME
在PostgreSQL,\ d TABLE_NAME
或者,你可以使用这个长的命令:
SELECT
a.attname AS Field,
t.typname || '(' || a.atttypmod || ')' AS Type,
CASE WHEN a.attnotnull = 't' THEN 'YES' ELSE 'NO' END AS Null,
CASE WHEN r.contype = 'p' THEN 'PRI' ELSE '' END AS Key,
(SELECT substring(pg_catalog.pg_get_expr(d.adbin, d.adrelid), '\'(.*)\'')
FROM
pg_catalog.pg_attrdef d
WHERE
d.adrelid = a.attrelid
AND d.adnum = a.attnum
AND a.atthasdef) AS Default,
'' as Extras
FROM
pg_class c
JOIN pg_attribute a ON a.attrelid = c.oid
JOIN pg_type t ON a.atttypid = t.oid
LEFT JOIN pg_catalog.pg_constraint r ON c.oid = r.conrelid
AND r.conname = a.attname
WHERE
c.relname = 'tablename'
AND a.attnum > 0
ORDER BY a.attnum
Answer 12:
这应该是解决方案:
SELECT * FROM information_schema.columns
WHERE table_schema = 'your_schema'
AND table_name = 'your_table'
Answer 13:
为了提高对对方的回答的SQL查询(这是伟大的!),这里是一个修改后的查询。 它也包括约束名称,继承的信息,并打破了数据类型转换为它的组成部分(类型,长度,精度刻度)。 它也过滤掉(在数据库中仍然存在)已经下降了列。
SELECT
n.nspname as schema,
c.relname as table,
f.attname as column,
f.attnum as column_id,
f.attnotnull as not_null,
f.attislocal not_inherited,
f.attinhcount inheritance_count,
pg_catalog.format_type(f.atttypid,f.atttypmod) AS data_type_full,
t.typname AS data_type_name,
CASE
WHEN f.atttypmod >= 0 AND t.typname <> 'numeric'THEN (f.atttypmod - 4) --first 4 bytes are for storing actual length of data
END AS data_type_length,
CASE
WHEN t.typname = 'numeric' THEN (((f.atttypmod - 4) >> 16) & 65535)
END AS numeric_precision,
CASE
WHEN t.typname = 'numeric' THEN ((f.atttypmod - 4)& 65535 )
END AS numeric_scale,
CASE
WHEN p.contype = 'p' THEN 't'
ELSE 'f'
END AS is_primary_key,
CASE
WHEN p.contype = 'p' THEN p.conname
END AS primary_key_name,
CASE
WHEN p.contype = 'u' THEN 't'
ELSE 'f'
END AS is_unique_key,
CASE
WHEN p.contype = 'u' THEN p.conname
END AS unique_key_name,
CASE
WHEN p.contype = 'f' THEN 't'
ELSE 'f'
END AS is_foreign_key,
CASE
WHEN p.contype = 'f' THEN p.conname
END AS foreignkey_name,
CASE
WHEN p.contype = 'f' THEN p.confkey
END AS foreign_key_columnid,
CASE
WHEN p.contype = 'f' THEN g.relname
END AS foreign_key_table,
CASE
WHEN p.contype = 'f' THEN p.conkey
END AS foreign_key_local_column_id,
CASE
WHEN f.atthasdef = 't' THEN d.adsrc
END AS default_value
FROM pg_attribute f
JOIN pg_class c ON c.oid = f.attrelid
JOIN pg_type t ON t.oid = f.atttypid
LEFT JOIN pg_attrdef d ON d.adrelid = c.oid AND d.adnum = f.attnum
LEFT JOIN pg_namespace n ON n.oid = c.relnamespace
LEFT JOIN pg_constraint p ON p.conrelid = c.oid AND f.attnum = ANY (p.conkey)
LEFT JOIN pg_class AS g ON p.confrelid = g.oid
WHERE c.relkind = 'r'::char
AND f.attisdropped = false
AND n.nspname = '%s' -- Replace with Schema name
AND c.relname = '%s' -- Replace with table name
AND f.attnum > 0
ORDER BY f.attnum
;
Answer 14:
您还可以检查使用以下查询
Select * from schema_name.table_name limit 0;
Expmple:我的表有两列名和pwd。 给下面的截图。
*使用PG口语陪练
Answer 15:
最好的方式来描述的表,诸如柱,类型,列的改性剂,等等。
\d+ tablename or \d tablename
Answer 16:
Use this command
\d table name
like
\d queuerecords
Table "public.queuerecords"
Column | Type | Modifiers
-----------+-----------------------------+-----------
id | uuid | not null
endtime | timestamp without time zone |
payload | text |
queueid | text |
starttime | timestamp without time zone |
status | text |
Answer 17:
In postgres \d is used to describe the table structure.
e.g. \d schema_name.table_name;
this command will provide you the basic info of table such as, columns, type and modifiers.
If you want more info about table use
\d+ schema_name.table_name;
this will give you extra info such as, storage, stats target and description
Answer 18:
/ dt为它列出了你存在的所有数据库中的表的commad。 运用
/ d命令和/ d +,我们可以得到一个表的细节。 该sysntax会像
* / d TABLE_NAME(或)\ d + TABLE_NAME
Answer 19:
我制定了GET表架构下面的脚本。
'CREATE TABLE ' || 'yourschema.yourtable' || E'\n(\n' ||
array_to_string(
array_agg(
' ' || column_expr
)
, E',\n'
) || E'\n);\n'
from
(
SELECT ' ' || column_name || ' ' || data_type ||
coalesce('(' || character_maximum_length || ')', '') ||
case when is_nullable = 'YES' then ' NULL' else ' NOT NULL' end as column_expr
FROM information_schema.columns
WHERE table_schema || '.' || table_name = 'yourschema.yourtable'
ORDER BY ordinal_position
) column_list;