我的要求是,我应该送一个10MB的zip文件到客户端与RESTful服务。 我发现在论坛上的代码,发送StreamingOutput
对象是更好的办法,但我怎么可以创建一个StreamingOutput
在下面的代码对象:
@Path("PDF-file.pdf/")
@GET
@Produces({"application/pdf"})
public StreamingOutput getPDF() throws Exception {
return new StreamingOutput() {
public void write(OutputStream output) throws IOException, WebApplicationException
{
try {
//------
} catch (Exception e) {
throw new WebApplicationException(e);
}
}
};
}
它的更好的方式和文件下载中心简单的方法。
private static final String FILE_PATH = "d:\\Test2.zip";
@GET
@Path("/get")
@Produces(MediaType.APPLICATION_OCTET_STREAM)
public Response getFile() {
File file = new File(FILE_PATH);
ResponseBuilder response = Response.ok((Object) file);
response.header("Content-Disposition", "attachment; filename=newfile.zip");
return response.build();
}
对于你的代码,你问:
@GET
@Path("/helloWorldZip")
@Produces(MediaType.APPLICATION_OCTET_STREAM)
public StreamingOutput helloWorldZip() throws Exception {
return new StreamingOutput(){
@Override
public void write(OutputStream arg0) throws IOException, WebApplicationException {
// TODO Auto-generated method stub
BufferedOutputStream bus = new BufferedOutputStream(arg0);
try {
//ByteArrayInputStream reader = (ByteArrayInputStream) Thread.currentThread().getContextClassLoader().getResourceAsStream();
//byte[] input = new byte[2048];
java.net.URL uri = Thread.currentThread().getContextClassLoader().getResource("");
File file = new File("D:\\Test1.zip");
FileInputStream fizip = new FileInputStream(file);
byte[] buffer2 = IOUtils.toByteArray(fizip);
bus.write(buffer2);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
};
}