透过Espresso点击查看RecyclerView项目内透过Espresso点击查看Recycle

如何使用咖啡点击一个RecyclerView项目内部的具体看法？我知道我可以在位置使用0单击该项目：

onView(withId(R.id.recyclerView)) .perform(RecyclerViewActions.actionOnItemAtPosition(0, click()));

但我需要点击该项目里面，而不是项目本身特定的视图。

提前致谢。

- 编辑 -

为了更精确：我有一个RecyclerView（ R.id.recycler_view ）哪些项目是CardView（ R.id.card_view ）。每个CardView里面我有四个按钮（除其他事项外），我想点击一个特定的按钮（ R.id.bt_deliver ）。

我想用咖啡2.0的新功能，但我不知道这是可能的。

如果没有可能，我想用这样的事情（使用托马斯凯勒代码）：

onRecyclerItemView(R.id.card_view, ???, withId(R.id.bt_deliver)).perform(click());

但我不知道该穿什么的问号。

Answer 1:

您可以使用自定义视图操作做到这一点。

public class MyViewAction {

    public static ViewAction clickChildViewWithId(final int id) {
        return new ViewAction() {
            @Override
            public Matcher<View> getConstraints() {
                return null;
            }

            @Override
            public String getDescription() {
                return "Click on a child view with specified id.";
            }

            @Override
            public void perform(UiController uiController, View view) {
                View v = view.findViewById(id);
                v.performClick();
            }
        };
    }

}

然后，你可以点击它

onView(withId(R.id.rv_conference_list)).perform(
            RecyclerViewActions.actionOnItemAtPosition(0, MyViewAction.clickChildViewWithId(R.id. bt_deliver)));

Answer 2:

现在，随着android.support.test.espresso.contrib它已经变得更加容易：

1）添加测试依赖

androidTestCompile('com.android.support.test.espresso:espresso-contrib:2.0') {
    exclude group: 'com.android.support', module: 'appcompat'
    exclude group: 'com.android.support', module: 'support-v4'
    exclude module: 'recyclerview-v7'
}

*排除3个模块，因为很可能你已经拥有了它

2）然后像做

onView(withId(R.id.recycler_grid))
            .perform(RecyclerViewActions.actionOnItemAtPosition(0, click()));

要么

onView(withId(R.id.recyclerView))
  .perform(RecyclerViewActions.actionOnItem(
            hasDescendant(withText("whatever")), click()));

要么

onView(withId(R.id.recycler_linear))
            .check(matches(hasDescendant(withText("whatever"))));

Answer 3:

尝试下方法：

    onView(withRecyclerView(R.id.recyclerView)
                    .atPositionOnView(position, R.id.bt_deliver))
                    .perform(click());

    public static RecyclerViewMatcher withRecyclerView(final int recyclerViewId) {
            return new RecyclerViewMatcher(recyclerViewId);
    }

public class RecyclerViewMatcher {
    final int mRecyclerViewId;

    public RecyclerViewMatcher(int recyclerViewId) {
        this.mRecyclerViewId = recyclerViewId;
    }

    public Matcher<View> atPosition(final int position) {
        return atPositionOnView(position, -1);
    }

    public Matcher<View> atPositionOnView(final int position, final int targetViewId) {

        return new TypeSafeMatcher<View>() {
            Resources resources = null;
            View childView;

            public void describeTo(Description description) {
                int id = targetViewId == -1 ? mRecyclerViewId : targetViewId;
                String idDescription = Integer.toString(id);
                if (this.resources != null) {
                    try {
                        idDescription = this.resources.getResourceName(id);
                    } catch (Resources.NotFoundException var4) {
                        idDescription = String.format("%s (resource name not found)", id);
                    }
                }

                description.appendText("with id: " + idDescription);
            }

            public boolean matchesSafely(View view) {

                this.resources = view.getResources();

                if (childView == null) {
                    RecyclerView recyclerView =
                            (RecyclerView) view.getRootView().findViewById(mRecyclerViewId);
                    if (recyclerView != null) {

                        childView = recyclerView.findViewHolderForAdapterPosition(position).itemView;
                    }
                    else {
                        return false;
                    }
                }

                if (targetViewId == -1) {
                    return view == childView;
                } else {
                    View targetView = childView.findViewById(targetViewId);
                    return view == targetView;
                }

            }
        };
    }
}

Answer 4:

这里，我怎么在科特林解决的问题：

fun clickOnViewChild(viewId: Int) = object : ViewAction {
    override fun getConstraints() = null

    override fun getDescription() = "Click on a child view with specified id."

    override fun perform(uiController: UiController, view: View) = click().perform(uiController, view.findViewById<View>(viewId))
}

然后

onView(withId(R.id.recyclerView)).perform(RecyclerViewActions.actionOnItemAtPosition<RecyclerView.ViewHolder>(position, clickOnViewChild(R.id.viewToClickInTheRow)))

Answer 5:

您可以点击 第三个项目 recyclerView就像这样：

onView(withId(R.id.recyclerView)).perform(
                RecyclerViewActions.actionOnItemAtPosition<RecyclerView.ViewHolder>(2,click()))

不要忘了提供ViewHolder类型，以便推断不会失败。

Answer 6:

首先给你的按钮独特contentDescriptions，即“交货按钮行5”。

<button android:contentDescription=".." />

然后滚动到行：

onView(withId(R.id.recycler_view)).perform(RecyclerViewActions.scrollToPosition(5));

然后选择基于contentDescription的看法。

onView(withContentDescription("delivery button row 5")).perform(click());

内容描述是用咖啡的onView，使您的应用程序更易于访问的好方法。

文章来源: Using Espresso to click view inside RecyclerView item