使用执行POST JSON / XML机器人-异步-HTTP（循环J）使用执行POST JSON /

我使用Android系统的异步HTTP和真正喜欢它。 我碰到与发布数据的问题。 我必须将数据发布到在下列格式API： -

<request>
  <notes>Test api support</notes>
  <hours>3</hours>
  <project_id type="integer">3</project_id>
  <task_id type="integer">14</task_id>
  <spent_at type="date">Tue, 17 Oct 2006</spent_at>
</request>

按照文件，我试图做它用RequestParams ，但失败了。 这是任何其他方式做到这一点？ 我可以张贴相当于JSON了。 有任何想法吗？

Answer 1:

循环J POST例子 - 延长从他们的Twitter例如：

private static AsyncHttpClient client = new AsyncHttpClient();

要通过正常发布RequestParams ：

RequestParams params = new RequestParams();
params.put("notes", "Test api support"); 
client.post(restApiUrl, params, responseHandler);

要发布JSON：

JSONObject jsonParams = new JSONObject();
jsonParams.put("notes", "Test api support");
StringEntity entity = new StringEntity(jsonParams.toString());
client.post(context, restApiUrl, entity, "application/json",
    responseHandler);

Answer 2:

@Timothy回答没有为我工作。

我所定义的Content-Type的的StringEntity ，使其工作：

JSONObject jsonParams = new JSONObject();
jsonParams.put("notes", "Test api support");

StringEntity entity = new StringEntity(jsonParams.toString());
entity.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));

client.post(context, restApiUrl, entity, "application/json", responseHandler);

祝好运 ：）

Answer 3:

更好的方式来发布JSON

RequestParams params = new RequestParams();
    params.put("id", propertyID);
    params.put("lt", newPoint.latitude);
    params.put("lg", newPoint.longitude);
    params.setUseJsonStreamer(true);

    ScaanRestClient restClient = new ScaanRestClient(getApplicationContext());
    restClient.post("/api-builtin/properties/v1.0/edit/location/", params, new AsyncHttpResponseHandler() {
        @Override
        public void onSuccess(int statusCode, Header[] headers, byte[] responseBody) {
        }

        @Override
        public void onFailure(int statusCode, Header[] headers, byte[] responseBody, Throwable error) {
        }
    });

Answer 4:

要发布XML

protected void makePost() {
    AsyncHttpClient client = new AsyncHttpClient();
    Context context = this.getApplicationContext();
    String  url = URL_String;
    String  xml = XML-String;
    HttpEntity entity;
    try {
        entity = new StringEntity(xml, "UTF-8");
    } catch (IllegalArgumentException e) {
        Log.d("HTTP", "StringEntity: IllegalArgumentException");
        return;
    } catch (UnsupportedEncodingException e) {
        Log.d("HTTP", "StringEntity: UnsupportedEncodingException");
        return;
    }
    String  contentType = "string/xml;UTF-8";

    Log.d("HTTP", "Post...");
    client.post( context, url, entity, contentType, new AsyncHttpResponseHandler() {
        @Override
        public void onSuccess(String response) {
            Log.d("HTTP", "onSuccess: " + response);
        }
          ... other handlers
    });
}

Answer 5:

只写你的XML或JSON字符串并发送至服务器，在适当的标题或无。 是的设置“内容类型”为“application / JSON”

Answer 6:

如果有人有HttpClient的发送是一个问题Content-Type: text/plain ，请参考以下链接： https://stackoverflow.com/a/26425401/361100

该循环J HttpClient的有所改变（或具有问题），其不能重写StringEntity天然内容类型到application/json 。

Answer 7:

您可以添加JSON字符串作为某种类型的InputStream的 - 我用ByteArrayStream，然后将它传递给您应该设置correctMimeType的RequestParams

InputStream stream = new ByteArrayInputStream(jsonParams.toString().getBytes(Charset.forName("UTF-8")));
multiPartEntity.put("model", stream, "parameters", Constants.MIME_TYPE_JSON);

Answer 8:

只是要的JSONObject，然后将其转换为字符串“someData”，并简单地用“ByteArrayEntity”送

    private static AsyncHttpClient client = new AsyncHttpClient();
    String someData;
    ByteArrayEntity be = new ByteArrayEntity(someData.toString().getBytes());
    client.post(context, url, be, "application/json", responseHandler);

这是对我工作的罚款。

Answer 9:

要发布的XML文件的PHP服务器：

public class MainActivity extends AppCompatActivity {

/**
 * Send xml file to server via asynchttpclient lib
 */

Button button;
String url = "http://xxx/index.php";
String filePath = Environment.getExternalStorageDirectory()+"/Download/testUpload.xml";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    button = (Button)findViewById(R.id.button);

    button.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            postFile();
        }
    });
}

public void postFile(){

    Log.i("xml","Sending... ");

    RequestParams params = new RequestParams();

    try {
        params.put("key",new File(filePath));
    }catch (FileNotFoundException e){
        e.printStackTrace();
    }

    AsyncHttpClient client = new AsyncHttpClient();

    client.post(url, params, new AsyncHttpResponseHandler() {
        @Override
        public void onSuccess(int i, cz.msebera.android.httpclient.Header[] headers, byte[] bytes) {
            Log.i("xml","StatusCode : "+i);
        }

        @Override
        public void onFailure(int i, cz.msebera.android.httpclient.Header[] headers, byte[] bytes, Throwable throwable) {
            Log.i("xml","Sending failed");
        }

        @Override
        public void onProgress(long bytesWritten, long totalSize) {
            Log.i("xml","Progress : "+bytesWritten);
        }
    });
}

}

加入Android的异步HTTP-1.4.9.jar到Android工作室后，去的build.gradle并添加： compile 'com.loopj.android:android-async-http:1.4.9'下的依赖

而在AndroidManifest.xml中添加：

<uses-permission android:name="android.permission.INTERNET" /> <uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" />

文章来源: POSTing JSON/XML using android-async-http (loopj)