尝试运行在MS SQL Server Management Studio中查询时OVERI我得到一个错误。 我们使用MS SQL Server 2005中的Windows 2003 Server上。
下面是该查询:
WITH q AS
(
SELECT *,
ROW_NUMBER() OVER (PARTITION BY dbo.[1_MAIN - Contacts].Contact_ID ORDER BY dbo.[1_MAIN - Contacts].Contact_ID) AS rn
FROM dbo.[1_MAIN - Contacts]
INNER JOIN
dbo.Referral
ON dbo.[1_MAIN - Contacts].Contact_ID = dbo.Referral.Referral_ID
INNER JOIN
dbo.prov_training_records
ON dbo.[1_MAIN - Contacts].Contact_ID = dbo.prov_training_records.Contact_ID
LEFT OUTER JOIN
dbo.Resource_Center
ON dbo.[1_MAIN - Contacts].Contact_ID = dbo.Resource_Center.Contact_ID
FULL OUTER JOIN
dbo.Providers
ON dbo.[1_MAIN - Contacts].Contact_ID = dbo.Providers.Contact_ID
)
SELECT *
FROM q
当我运行它,我只是出现以下信息弹出窗口:
窗口标题 - “查询定义不同”
描述 - “在解析SQL窗格中的内容时遇到下列错误:”
错误 - “不支持OVER SQL构造或语句。”
然后在最后它说 - “查询不能在图和条件窗格图形表示。”
不过,我没有图或标准窗格打开。
我需要确保我们拥有正确的语法。 如果语法正确,那么我要么需要修复为什么Management Studio中抛出这个错误,或者找到一个解决过度,并用不同的方法解决这个问题。
我知道,规范说“OVER”是支持的,但我得到的错误。
在新的查询窗口,如果我运行这个它的工作原理:
USE abtcontacts;
WITH q AS
(
SELECT dbo.[1_MAIN - Contacts].Contact_ID, dbo.[1_MAIN - Contacts].Date_entered_into_Database, dbo.[1_MAIN - Contacts].Date_of_Initial_Contact,
dbo.[1_MAIN - Contacts].[Company_ Name], dbo.[1_MAIN - Contacts].Key_Contact_Title, dbo.[1_MAIN - Contacts].Key_Contact_First_Name,
dbo.[1_MAIN - Contacts].Key_Contact_Middle, dbo.[1_MAIN - Contacts].Key_Contact_Last_Name, dbo.[1_MAIN - Contacts].Key_Credential,
dbo.[1_MAIN - Contacts].Key_Contact_Occupation, dbo.[1_MAIN - Contacts].Key_Degree_1, dbo.[1_MAIN - Contacts].Key_Degree_2,
dbo.[1_MAIN - Contacts].Key_Degree_3, dbo.[1_MAIN - Contacts].Date_of_Highest_Degree, dbo.[1_MAIN - Contacts].Work_Setting,
dbo.[1_MAIN - Contacts].Website_Address, dbo.[1_MAIN - Contacts].Email_1_Key_Contact, dbo.[1_MAIN - Contacts].Email_2,
dbo.[1_MAIN - Contacts].Email_3, dbo.[1_MAIN - Contacts].Day_Time_Phone_Number, dbo.[1_MAIN - Contacts].Extension,
dbo.[1_MAIN - Contacts].Mobile_Phone_Number, dbo.[1_MAIN - Contacts].Bus_Fax_Number, dbo.[1_MAIN - Contacts].Home_Phone_Number,
dbo.[1_MAIN - Contacts].Home_Fax_Number, dbo.[1_MAIN - Contacts].Mailing_Street_1, dbo.[1_MAIN - Contacts].Mailing_Street_2,
dbo.[1_MAIN - Contacts].Mailing_City, dbo.[1_MAIN - Contacts].Mailing_State, dbo.[1_MAIN - Contacts].[Mailing_Zip/Postal],
dbo.[1_MAIN - Contacts].Mailing_Country, dbo.[1_MAIN - Contacts].[Bad_Address?], dbo.[1_MAIN - Contacts].[PROV/REG?],
dbo.[1_MAIN - Contacts].status_flag, dbo.[1_MAIN - Contacts].status_flag AS status_flag2, dbo.Providers.Referral_Source, dbo.Referral.Contact_Source,
dbo.Resource_Center.cert_start_date, dbo.Resource_Center.cert_exp_date, dbo.prov_training_records.Contact_ID AS Expr2,
dbo.prov_training_records.date_reg_email_sent, dbo.Resource_Center.access, dbo.Providers.Contact_ID AS Expr1,
ROW_NUMBER() OVER (PARTITION BY dbo.[1_MAIN - Contacts].Contact_ID ORDER BY dbo.[1_MAIN - Contacts].Contact_ID) AS rn
FROM dbo.[1_MAIN - Contacts]
INNER JOIN
dbo.Referral
ON dbo.[1_MAIN - Contacts].Contact_ID = dbo.Referral.Referral_ID
INNER JOIN
dbo.prov_training_records
ON dbo.[1_MAIN - Contacts].Contact_ID = dbo.prov_training_records.Contact_ID
LEFT OUTER JOIN
dbo.Resource_Center
ON dbo.[1_MAIN - Contacts].Contact_ID = dbo.Resource_Center.Contact_ID
FULL OUTER JOIN
dbo.Providers
ON dbo.[1_MAIN - Contacts].Contact_ID = dbo.Providers.Contact_ID
)
SELECT *
FROM q
WHERE rn = 1
解决这一问题将有助于我解决我的另外一个问题在这里